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WHAT IS THE MAGNIFYING POWER OF A COMPOUND MICROSCOPE?.
 The magnifying power of the compound microscope may be expressed as M = mo × me; where mo is the magnification of the objective and me is magnifying power of eye piece.

 Example 1: The length of the compound microscope is 14 cm. The magnifying power for relaxed eye is 25. If the focal length of eye lens is 5 cm, then the object distance for objective lens will be

(A) 1.8 cm       (B) 1.5 cm             (C) 2.1 cm             (D) 2.4 cm

Solution: (A) L? = vo + fe => 14 = vo + 5 => vo = 9 cm

Magnifying power of microscope for relaxed eye

m = vo/uo.D/fe or 25 = 9/uo.25/5 or uo = 9/5 = 1.8 cm


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