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State and prove parallelogram law of vectors and discuss the special cases. |
Parallelogram law of vectors If two vectors acting at a point are represented in magnitude and direction by the two adjacent sides of a parallelogram, then their resultant is represented in magnitude and direction by the diagonal passing through the common tail of the two vectors. Let us consider two vectors CD is drawn perpendicular to the extended OA, from C. Let From right angled triangle OCD, OC2 = OD2 + CD2 = (OA + AD)2 + CD2 = OA2 + AD2 + 2.OA.AD + CD2 (1) From right angled ? CAD, AC2 = AD2 + CD2 (2) Substituting (2) in (1) OC2 = OA2 + AC2 + 2OA.AD (3) From ? ACD, CD = AC sin ? (4) AD = AC cos ? (5) Substituting (5) in (3) OC2 = OA2 + AC2 + 2 OA.AC cos ? Substituting OC = R, OA = P, OB = AC = Q in the above equation R2 = P2 + Q2 + 2PQ cos ? (or) Equation (6) gives the magnitude of the resultant. From ? OCD, Substituting (4) and (5) in the above equation,
Equation (7) gives the direction of the resultant. Special Cases (i) When two vectors act in the same direction In this case, the angle between the two vectors ? = 0°, cos 0° = 1, sin 0° = 0 From (6) From (7) That is ? = 0 Thus, the resultant vector acts in the same direction as the individual vectors and is equal to the sum of the magnitude of the two vectors. (ii) When two vectors act in the opposite direction In this case, the angle between the two vectors ? = 180°, cos 180° = -1, sin 180° = 0. From (6) From (7) Thus, the resultant vector has a magnitude equal to the difference in magnitude of the two vectors and acts in the direction of the bigger of the two vectors (iii) When two vectors are at right angles to each other In this case, ? = 90°, cos 90° = 0, sin 90° = 1 From (6) From (7) The resultant |