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The correct order of decreasing second I.E of Ti,V,Cr,Mn is a)Mn>Cr>Ti>V b)Ti>V>Cr>Mn c)V>Mn>Cr>Ti d)Cr>Mn>V>Ti
ANS:D
Due to an increase in nuclear charge which accompanies the filling
of the inner d orbitals, there is an increase in ionisation enthalpy
along each series of the transition elements from left to right. However,
many small variations occur. The dominant term
is the second ionisation enthalpy which shows unusually high values
for Cr and Cu where the d5 and d10 configurations of the M ions are
disrupted, with considerable loss of exchange energy.


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