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Question-1 

Percentage composition of an organic compound as determined by analysis was carbon 14.5, hydrogen 1.8, chlorine 64.46, and oxygen 19.24. The empirical formula of the compound is


(A)

CH3Cl3O2


(B)

CH2Cl2O

(C)

CH3Cl2O

(D)

C2H3Cl3O2





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