Sin^-1 (¹/_x)  =

The principal value of sin^-1 (¹/₂)

tan^-1 (¹/₇) + tan^-1 (¹/₁₃) =

Sin (¹/₂ cos^{-1 4}/₅)

The value of is

The value of tan 40^o + tan 20^o + √3 tan 20^o tan 40^o is equal to

ΔABC is right angled at C, then tan A + tan B is equal to.

Sin (cos^-1 (³/₅)  =

cos 15^o =

Cos (tan^{-1 3}/₄) =