Sin^-1 (¹/_x)  =

Solution of tan^-12x + tan^-1 3 x = ^π/₄

Cos (tan^{-1 3}/₄) =

tan (735^o)  = tan (2 × 360^o + 15^o)

Sin (¹/₂ cos^{-1 4}/₅)

The value of is

ΔABC is right angled at C, then tan A + tan B is equal to.

The product s(s-a)  (s-b) (s-c) is equal to

The value of tan 40^o + tan 20^o + √3 tan 20^o tan 40^o is equal to

Area of Δ ABC is