Sin (cos-1 (3/5) =
1/5
3/4
4/5
1/3
Sin (1/2 cos-1 4/5)
Cos (tan-1 3/4) =
2/5
1/4
Solution of tan-12x + tan-1 3 x = π/4
-1 or 1/6
1 or -1/6
-1 or 6
1 or -6
Cos4 A - Sin4 A =
2 Sin2 A - 1
1 - 2 Sin2 A
2 Cos2 A - 1
1 -2 Cos2 A
The principal value of sin-1 (1/2)
π
π/2
π/6
0
The value of is
2
1
√2
Sin-1 (1/x) =
sin x
cosec-1x
cos x
cos (1/x)
ΔABC is right angled at C, then tan A + tan B is equal to.
a + b
Area of Δ ABC is
1/2 ab cos C
1/2 ab sin c
1/2 ab cos B
1/2 ca sin B
