Solution of tan-12x + tan-1 3 x = π/4
-1 or 1/6
1 or -1/6
-1 or 6
1 or -6
If sin-1 (1/2) = tan-1 x, find the value of x
√3
1/2
Sin-1 (1/x) =
sin x
cosec-1x
cos x
cos (1/x)
Sin (1/2 cos-1 4/5)
The value of is
2
1
√2
Sin (cos-1 (3/5) =
1/5
3/4
4/5
1/3
0
3
tan-1 (1/7) + tan-1 (1/13) =
tan-1(1/9)
tan-1 (20)
tan-1(2/9)
tan-1(3/4)
Cos (tan-1 3/4) =
2/5
1/4
The product s(s-a) (s-b) (s-c) is equal to
Δ
Δ2
2 Δ
Δ/s
