Solution of tan-12x + tan-1 3 x = π/4
-1 or 1/6
1 or -1/6
-1 or 6
1 or -6
Sin (1/2 cos-1 4/5)
Cos (tan-1 3/4) =
4/5
2/5
1/4
3/4
In a ΔABC, ∠A = π/2, then cos2 B + cos2 C equals
-2
-1
1
0
The value of is
3/16
3/8
1/2
2
3
√2
ΔABC is right angled at C, then tan A + tan B is equal to.
a + b
The value of tan 40o + tan 20o + √3 tan 20o tan 40o is equal to
√12
1/√3
√3
√3/2
Cos4 A - Sin4 A =
2 Sin2 A - 1
1 - 2 Sin2 A
2 Cos2 A - 1
1 -2 Cos2 A
