If sin-1 (1/2) = tan-1 x, find the value of x
√3
1/2
ΔABC is right angled at C, then tan A + tan B is equal to.
a + b
The value of is
3/16
3/8
3/4
Sin (cos-1 (3/5) =
1/5
4/5
1/3
Solution of tan-12x + tan-1 3 x = π/4
-1 or 1/6
1 or -1/6
-1 or 6
1 or -6
Cos4 A - Sin4 A =
2 Sin2 A - 1
1 - 2 Sin2 A
2 Cos2 A - 1
1 -2 Cos2 A
Sin (1/2 cos-1 4/5)
Cos (tan-1 3/4) =
2/5
1/4
The product s(s-a) (s-b) (s-c) is equal to
Δ
Δ2
2 Δ
Δ/s
The value of tan 40o + tan 20o + √3 tan 20o tan 40o is equal to
√12
1/√3
√3/2
