If the radius of the earth decreases by 10%, the mass remaining unchanged, what will happen to the acceleration due to gravity?

A satellite moves eastwards very near the surface of the earth in the equatorial plane of the earth with speed v₀. Another satellite moves at the same height with the same speed in the equatorial plane but westwards. If R is the radius of the earth and ω be its angular speed about its own axis, then the difference in the two time period as observed on the earth will be approximately equal to :

If the radius of the earth is made three times, keeping its mass constant, then the weight of a body on earth's surface will be as compared to its previous value :

The time period of a satellite of earth is 5h. If the separation between the earth and the satellite is increased to 4 times the previous value, the new time period will become :

A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11kms^-1, the escape velocity from the surface of the planet would be :

The radius of earth is 6400 km and the value of g is 10m/s² . If the weight of 5km body on the equator becomes zero, then the angular speed of earth will be :

A satellite of mass m revolves around the earth of the radius R at a height x from its surface. It g is the acceleration due to gravity on the surface of the earth, the orbital speed of the satellite is :

The escape velocity of a body depends upon mass as :

g_e and g_p are accelerations due to gravity on the surface of earth and a planet respectively. The radius and mass of the planet are double the radius and mass of earth. Then :

Energy required to move a body of mass m from an orbit of radius 2R to 3R is :