The kinetic energy needed to project a body of mass m from the earth's surface (radius R) to infinity is :
mgR
2mgR
The radius of earth is 6400 km and the value of g is 10m/s2 . If the weight of 5km body on the equator becomes zero, then the angular speed of earth will be :
A satellite is revolving round the earth. Its K.E is Ek. How much would it be made so that the satellite may escape out of the gravitational field of earth?
2Ek
3Ek
Ek/2
Infinite
A planet of mass M is revolving round the sun of mass Ms in an elliptical orbit. The maximum and minimum distance of the planet from sun are r1 and r2 respectively. Then :
ge and gp are accelerations due to gravity on the surface of earth and a planet respectively. The radius and mass of the planet are double the radius and mass of earth. Then :
ge = gp
ge = 2gp
gp = 2ge
ge = √2gp
The escape velocity of a body depends upon mass as :
m2
m3
m0
m1
If suddenly the gravitational force of attraction between earth and a satellite revolving around it becomes zero, then the satellite will :
become stationary in its orbit
move towards the earth
continue to move in its orbit with same velocity
move tangentially to the original orbit with the same velocity
The time period of an earth satellite in circular orbit is independent of :
both the mass and radius of the orbit
neither the mass of the satellite nor the radius of its orbit
the mass of the satellite
radius of its orbit
Suppose the gravitational force varies inversely as the nth power of distance. Then the time period of a planet in circular orbit of radius R around the sun will be proportional to :
Rn
A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 times smaller. Given that the escape velocity from the earth is 11kms-1, the escape velocity from the surface of the planet would be :
110 kms-1
0.11 kms-1
1.1 kms-1
11 kms-1
