The displacement x (in metres) of a particle performing S.H.M is related to time t (in second) as :
0.5 Hz
1.0 Hz
1.5 Hz
2.0 Hz
A wave has SHM (simple harmonic motion) whose period is 4 s while another wave which also possesses SHM has its period 3 s. If both are combined, then the resultant wave will have the period equal to
4 s
5 s
12 s
3 s
A body is vibrating in S.H.M. with an amplitude of 0.06 m and frequency of 15 Hz. The maximum velocity and acceleration of the body are
5.65 m/s, 5.32 x 102 m/s2
6.82 m/s, 7.62 x 102 m/s2
8.91 m/s, 8.21 x 102 m/s2
9.82 m/s, 9.03 x 102 m/s2
A body is executing S.H.M When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocities are 10 cm/sec and 8cm/sec. Then time period of the body is
Frequency of a simple pendulum in a freely falling lift is
zero
infinite
finite
cannot say
A particle is performing simple harmonic motion along x axis with amplitude 4 cm and time period 1.2 sec. The minimum time taken by the particle to move from x = + 2 cm to x = + 4 cm and back again is
0.4 s
0.3 s
0.2 s
0.6 s
If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0m/s2 at any time, the angular frequency of the oscillator is equal to
10 rad/s
0.1 rad/s
100 rad/s
1 rad/s
The total energy of a body performing S.H.M. depends on
k,a,m
k,a,x
k,a
k,x
A particle executing S.H.M has amplitude 0.01 m and frequency 60 Hz. The maximum acceleration of the particle is
A particle executes simple harmonic motion of amplitude A. At what distance from the mean position its kinetic energy is equal to its potential energy ?
0.51 A
0.61 A
0.71 A
0.81 A
