None of these
Let f: R →R be a function defined by
f( x ) = 2x + 1. Then f -1 is
x -1
(x - 1)/2
x + 1
(x + 1)/2
If f(x) = x + 1/x , then which of the following is correct?
[ f (x) ]3 = f (x)3 + 3 f (x)
[ f (x) ] 3 = f (x)3 - 3 f (1/x)
[ f (x) ]3 = f (x 3 )+ 3 f (1/x)
f (x)3 = (f [x])3 - 3 f (x)
Let f, g : R → R be defined by f ( x ) = 2 x + 1, and g ( x ) = x-1/2, then find fog
x2
x/2
2 x
x
Domain of f (x) = is
R - { -2, 2 }
R - {-1, 1 }
R - { 2 }
R
Range of f (x) = is
(0, ∞ )
(0, 5 )
(5, ∞ )
(-5, 5 )
If each element of the range is associated with exactly one element of the domain, then it is said to be _______ function.
On to
One to one
Inverse
Identity
Let A = { 1, 2}, B = { 3, 4 } and C = { 5, 6 } and F : A → B and g : B → c Such that f ( 1 ) = 3, f ( 2 ) = 4, g ( 3 ) = 5, g ( 4 ) = 6, then go f =
{ (1, 3 ) ( 2, 4 )}
{ (1, 5), ( 2, 6 )}
{ (, 2 ) ( 5, 6 ) }
{ ( 3, 5 ) ( 4, 6 ) }
Domain of f (x) = is.
R - { -4 }
R - {4}
R - {2}
The function f : R → R defined by f ( x ) = x + 1 is
Injective
Bijective
