The two functions f : R → R. g : R → R are defined by f (x ) = x2 + 1, g ( x ) = x -1, then gof =
x2 - 2
x2 - 2 x + 2
x2
2 x
The domain of the rational function
R
R - { 0 }
R - { 0, 1}
R - { 0, 2 }
If f(x) = x + 1/x , then which of the following is correct?
[ f (x) ]3 = f (x)3 + 3 f (x)
[ f (x) ] 3 = f (x)3 - 3 f (1/x)
[ f (x) ]3 = f (x 3 )+ 3 f (1/x)
f (x)3 = (f [x])3 - 3 f (x)
Let f: R →R be a function defined by
f( x ) = 2x + 1. Then f -1 is
x -1
(x - 1)/2
x + 1
(x + 1)/2
Domain of f (x) = is
R - { -2, 2 }
R - {-1, 1 }
R - { 2 }
The function f : R → R defined by f ( x ) = x + 1 is
Injective
Bijective
Inverse
Identity
If each element of the range is associated with exactly one element of the domain, then it is said to be _______ function.
On to
One to one
The two functions f: R → R, g : R → R are defined by f ( x ) = x2 + 1, g ( x ) = x -1. then fog =
x2 + 2 x + 2
x2 + 2 x
None of these
Range of function f (x) = is.
( -∞, 1 )
(-∞, 1 ]
(1, ∞ )
(0, ∞ ]
