A cone whose height is always equal to its diameter is increasing in Volume at the rate of 40 cm2 /sec . At what rate is the radius increasing when its circular base area is 1m2 ?
1mm/sec
0.001 cm/sec
2 mm/sec
0.002 cm/sec
The radius of a sphere is changing at the rate of 0.1 cm/sec. The rate of change of its surface area when the radius is 200 cm is
The point on the curve y =2 x2 - 6 x - 4 at which the tangent is parallel to the x - axis is
The gradient of the curve y = at x = 2 is
-20
27
-16
-21
The slope of the tangent to the curve y = 3 x2 +3 sinx at x = 0 is
3
2
1
-7
For what values of x, the rate of increase of x3 -5 x2 +5 x+6 is twice the rate of increase of x ?
1, 7/3
3, 1/3
3, 7/3
1/3,7/3
The equation of the tangent to the curve at the point is
5 y + 3 x = 2
5 y - 3 x = 2
3 x + 3 y = 2
If the length of the diagonal of a square is increasing at the rate of 0.1 cm/sec. What is the rate of increase of its area when the side is 15/√2 cm ?
5
3√2
0. 15
What is the surface area of a sphere when the volume is increasing at the same rate as its radius?
1/2λ
4λ
The value of
