If A, B, C, D are the angle of a cyclic quadrailater at, then cos A + cos B + cos C+ cos D is equal to
2 (cos A + cos C)
2 (cos A + Cos B)
2 (cos A + cos D)
0
Sinθ*cosecθ =
1
180
none
Cos4 A- sin4A=
(cos2A-sin2A)2
(cos2A+ sin2A)
1-2 sin2A
1-2 cos2A
If √3 sec θ +2 = 0 , the general value of θ is
2 n π ± 2 π/3
2 n π ± π/6
2 n π ± π/3
2 n π ± 5 π/6
The general solution of sinx - 3 sin 2x+ sin 3x= cosx -3 cos2x + cos 3 x is
n π+ π/8
n π/2+ π/8
(-1)n(nπ/2)+π/8
2nπ+cos-1 (3/2)
If θ =π/4, then 1+ tan 2 θ =
sin 2 θ
cot 2 θ
cosec2 θ
sec 2 θ
The equation sinx+ cosx = 2 has
Infinite solutions
Two solutions
Unique solution
No solution
Sin 90o =
∝
None
If sec2 θ = 4/3, the general value of θ is
n π ± π/6
n π ± π/3
