1 - cos2θ - sin2θ =
1
2
0
3
1+tan2θ =
cos2θ
sec2θ
cosec2θ
cot2θ
Sinθ*cosecθ =
180
none
If cos θ = -5/12 in which quadrant does θ lie ?
I quadrand
II quadrand
III quadrand
II or III
If θ =π/4, then 1+ tan 2 θ =
sin 2 θ
cot 2 θ
cosec2 θ
sec 2 θ
____________=1+tan2θ
If 2 cos2x + 3 sin x -3 = 0, 0≤ x,≤1800, then x =
300, 900,1500
600,1200,1800
00,300,1500
450, 900,1350
If √3 sec θ +2 = 0 , the general value of θ is
2 n π ± 2 π/3
2 n π ± π/6
2 n π ± π/3
2 n π ± 5 π/6
(1+ tanA)2 + (1-tanA)2 =
sec2A
secA
2sec2A
