1 - cos2θ - sin2θ =
1
2
0
3
1+tan2θ =
cos2θ
sec2θ
cosec2θ
cot2θ
The value of cos 1o cos 2o cos 3o .... cos 100o =
-b
None of these
The equation sinx+ cosx = 2 has
Infinite solutions
Two solutions
Unique solution
No solution
Sin 90o =
∝
None
Sinθ*cosecθ =
180
none
If A, B, C, D are the angle of a cyclic quadrailater at, then cos A + cos B + cos C+ cos D is equal to
2 (cos A + cos C)
2 (cos A + Cos B)
2 (cos A + cos D)
If θ =π/4, then 1+ tan 2 θ =
sin 2 θ
cot 2 θ
cosec2 θ
sec 2 θ
The general solution of sinx - 3 sin 2x+ sin 3x= cosx -3 cos2x + cos 3 x is
n π+ π/8
n π/2+ π/8
(-1)n(nπ/2)+π/8
2nπ+cos-1 (3/2)
If 2 cos2x + 3 sin x -3 = 0, 0≤ x,≤1800, then x =
300, 900,1500
600,1200,1800
00,300,1500
450, 900,1350
