The equation of the line joining the points (1,4) and (3,10) is.
y = 3x-1
y = 3x+1
y = -3x-1
In the equation of the line y= mx+c where m and c are constants,c is called
x- intercept
y- intercept
x- coordinate
y-coordinate
The equation of the line through the point (-2,5) which is perpendicular to the line y= 3x+1 is.
x+ 3y = 13
x -3y = 13
x + 3y = -13
x- 3y = -13
The co-ordinates of the midpoints of the line segment joining the points (2,11) and (6,15) are.
(8,26)
(6,13)
(4,11)
(4,13)
The length of the line segment joining the points (p+ 4q, p-q) and (p- 3q,p) is.
The coordinates of the midpoint of the line segment joining the points (p+2q, 2p+13q) and (5p-2q, -2p-7q) is.
(p,q)
(2p,2q)
(3p, 3q)
(4p,4q)
The equation of the line through the point (1,1) which is perpendicular to the line 2x-3y=12 is.
3x - 2y = 5
3x + 2y = 5
3x - 2y = -5
3x+ 2y = -5
The equation of the straight lines through the point (2,3) with gradient 5 is.
y = 5x+7
y = -5x + 7
y = 5x - 7
y = -5x - 7
The gradient of the line 2x+y=7 is.
2
-2
7
-7
Two lines with gradient m1 and m2 are perpendicular if.
m1m2 = -1
m1m2 = 1
m1- m2 = -1
m1/m2 = -1
