The period of cos(x)2 is
2π
4π2
π2/4
None of these
f(a2)
f(a)
f(a+1)
The inverse function of f(x) = [1 - (x - 5)3]1/5 is
5 + (1 - x5)1/3
5 - (1 - x2)1/3
-5 + (1 - x5)1/3
If f(x) = x2 - 1/x2, f(x) =
-f(1/x)
f(1/x)
-f(x)
f(x2)
If f(x) = x2-5x+3, then f(1) =
3
1
0
-1
Cot θ
-tan θ
- Cot θ
- sin θ
The domain of the function f(x) = log |4 - x2| is
(-2, 2)
R - {2, -2}
{-2, 2}
The period of f(x) = sin4x + cos4x is
π
π/2
4π
Given f: N→N, If f={(1,3) (2,5) (3,7).........} then f(x)=
2x + 1
2x - 1
x + 1
x - 1
