A particle starts simple harmonic motion from the mean position. Its amplitude is a and time period is T. What is its displacement when its speed is half of its maximum speed ?
A particle starts S.H.M from the mean position. Its amplitude is A and time period is T. At the time its speed is half of the maximum speed. Its displacement y from the mean position is
√(3A/2)
The acceleration of a particle performing S.H.M. is 12 cm/sec2 at a distance of 4 cm from the mean position. Its time period is
2.0 sec
3.14 sec
0.5 sec
1.0 sec
In a simple harmonic motion, when the displacement is one-half the amplitude, what fraction of the total energy is kinetic ?
Zero
The acceleration of a particle in S.H.M. is
always constant
maximum at extreme positions
maximum at mean position
always zero
A particle of mass 200 g executes S.H.M. The restoring force is provided by a spring of force constant 80 N/m. The time period of oscillations is
0.15 sec
0.02 sec
0.31 sec
0.05 sec
A particle is subjected to two mutually perpendicular simple harmonic motions such that is x and y coordinates are given byThe path of the particle will be
a straight line
a circle
an ellipse
a parabola
A particle executes simple harmonic motion of amplitude A. At what distance from the mean position its kinetic energy is equal to its potential energy ?
0.51 A
0.61 A
0.71 A
0.81 A
Frequency of a simple pendulum in a freely falling lift is
zero
infinite
finite
cannot say
