In a simple harmonic motion, if the displacement is half of the amplitude, then which part of total energy will be kinetic energy ?
1/3
3/4
2/3
1/4
If metal bob of a simple pendulum is replaced by a wooden bob, then its time period will
increase
decrease
remain the same
first (a), then (b)
The acceleration of a particle performing S.H.M. is 12 cm/sec2 at a distance of 4 cm from the mean position. Its time period is
2.0 sec
3.14 sec
0.5 sec
1.0 sec
A particle is performing simple harmonic motion along x axis with amplitude 4 cm and time period 1.2 sec. The minimum time taken by the particle to move from x = + 2 cm to x = + 4 cm and back again is
0.4 s
0.3 s
0.2 s
0.6 s
A wave has SHM (simple harmonic motion) whose period is 4 s while another wave which also possesses SHM has its period 3 s. If both are combined, then the resultant wave will have the period equal to
4 s
5 s
12 s
3 s
A simple pendulum with a bob of mass m oscillates from A to C and back to A [See Fig.] such that PB is H. If the acceleration due to gravity is g then velocity of the bob as it passes through B is
zero
2gH
mgH
A particle of mass 200 g executes S.H.M. The restoring force is provided by a spring of force constant 80 N/m. The time period of oscillations is
0.15 sec
0.02 sec
0.31 sec
0.05 sec
A particle is executing S.H.M of amplitude 4 cm and T = 4 sec. The time taken by it to move from positive extreme position to half the amplitude is
1 sec
1/3 sec
2/3 sec
A body is executing S.H.M When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocities are 10 cm/sec and 8cm/sec. Then time period of the body is
