A particle of mass 10 g is executing S.H.M, with an amplitude of 0.5 m and periodic time of second. The maximum value of force acting on the particle is
25 N
5 N
2.5 N
0.5 N
In a simple harmonic motion, if the displacement is half of the amplitude, then which part of total energy will be kinetic energy ?
1/3
3/4
2/3
1/4
A particle is executing S.H.M. with an amplitude of 4 cm and time period 12 seconds. The time taken by the particle in going 2 cm from the mean position is T1 seconds. The time taken from this displaced position to reach the extreme position on the same side is T2 seconds. Then T1 /T2 will be
Two springs A and B (kA =3kB )are stretched by the same suspended weight. Then ratio of work done in stretching is
1 : 2
1 : 3
1 : 4
2 : 1
In a simple harmonic motion, when the displacement is one-half the amplitude, what fraction of the total energy is kinetic ?
Zero
The acceleration of a particle performing S.H.M. is 12 cm/sec2 at a distance of 4 cm from the mean position. Its time period is
2.0 sec
3.14 sec
0.5 sec
1.0 sec
The acceleration of a particle in S.H.M. is
always constant
maximum at extreme positions
maximum at mean position
always zero
A particle is executing S.H.M of amplitude 4 cm and T = 4 sec. The time taken by it to move from positive extreme position to half the amplitude is
1 sec
1/3 sec
2/3 sec
A linear harmonic oscillator of force constant 2 x 106 N/m and amplitude 0.01 m has a total mechanical energy of 160 J. Its
maximum potential energy is 160 J
maximum potential energy is 100 J
maximum potential energy is zero
minimum potential energy is 100 J
