The densities of graphite and diamond at 298 K are 2.25 and 3.31 g cm-3 , respectively. If the standard free energy difference (ΔGo ) is equal to 1895 J mol-1, the pressure at which graphite will be transformed into diamond at 298 K is
9.92 × 106 Pa
9.92 × 105 Pa
9.92 × 108 Pa
9.92 × 107 Pa
The enthalpy of combustion of H2, cyclohexene (C6H10) and cyclohexane (C6H12) are - 241, -3800 and -3920 kJ per mol respectively. Heat of hydrogenation of cyclohexene is
- 121 kJ per mol
+ 121 kJ per mol
+ 242 kJ per mol
- 242 kJ per mol
2 moles of an ideal gas at 270 C temperature is expanded reversibly from 2 L to 20 L. Find entropy change (R = 2 cal/mol K).
92.1
0
4
9.2
PbO2→PbO,G298 < 0
SnO2→ SnO,G298 > 0
Most probable oxidation state of Pb and Sn will be
Pb4+, Sn4+
Pb4+, Sn2+
Pb2+, Sn2+
Pb2+, Sn4+
Enthalpy of the reaction, is negative. If enthalpy of combustion of CH4 and CH3OH are x and y are respectively, then which relation is correct ?
x > y
x < y
x = y
x ≥ y
Assume each reaction is carried out in an open container. For which reaction will ΔH =f ΔE ?
H(g) + Br(g) → 2HBr(g)
C(s) + 2H2O(g) → 2H2 (g) + CO2 (g)
PCI5(g) → PCI3 (g) + CI2 (g)
2 CO (g) + O2 (g) → 2CO2 (g)
Which of the following are not state functions ?
(I) q + W (II) q
(III) W (IV) H - TS
(I) and (IV)
(II), (III) and (IV)
(I), (II) and (III)
(II) and (III)
For which one of the following equations equal to for the product ?
Xe(g) + 2F2 (g) → XeF4 (g)
2CO(g) + O2 (g) → 2CO2 (g)
N2(g) + O3 (g) → N2 O3(g)
CH4(g) + 2CI2 (g) → CH2 CI2 (l) + 2HCI (g)
If enthalpies of formation of C2H4(g), CO2(g) and H2O(l) at 25oC and 1 atm pressure are 52, -394 and -286 kJ/mol, the enthalpy of combustion of ethene is equal to
-141.2 kJ/mol
-1412 kJ/mol
+14.2 kJ/mol
+1412 kJ/mol
Given the following entropy values (in JK-1 mol-1) at 298 K and 1 atm : H2(g) : 130.6, CI2(g) : 223.0, HCI(g) : 186.7. The entropy change (in Jk-1 mol-1) for the reaction
H2(g) + CI2(g) → 2HCI(g), is
+ 540.3
+ 727.0
- 166.9
+ 19.8
