The relation ≥ on the set R of all real numbers is
Reflexive
Symmetric
Transitive
Both (1) and (3)
For real numbers x and y, are wirte x R y . x2-y2+√3 is irrational number. Then the relation R is
None of these
Let A= {2,3,4,5} and Let R= {(2,3), (2,4), (2,5) } be a relation in A. Then R is
Cartesian product of two sets A and B is Ax B =
{(a,b); aA and bB}
{x; xA and B}
{(a,b); aB and bA}
If A, B and C are non empty sets then Ax (B C)=
(AxB) (AxC)
(AxC) (AxA)
(AxB) (BxC)
Domain of the relation {(-3,1) (-1,1) (1,0) (3,0)} is
{-3,-1,-1,3}
{-3,-1,1,3}
{1,1,0}
{1,0}
Two finite sets A and B having m and n elements. The total number of relation A to B is 64, then possible values of m and n are.
2 and 4
2 and 3
2 and 1
64 and 1
If A = {1,2,3,4} and B= {5,6,7}, then number of relations from A to B is equal to
24
23
27
212
If R is a relation from {11,12,13} to { 8,10,12} and is defined by y= x-3, then find teh value of R-1.
{ (11,8), (10,13)}
{ (8,11), (10,13)}
{ (11,10), (8,13)}
{ (8,10), (11,13)}
