A mass m is vertically suspended from a spring of negligible mass; the system oscillates with a frequency n.What will be the frequency of the system, if a mass 4 m is suspended from the same spring ?

A body executes SHM with an amplitude .  At what displacement from the mean position is the potential energy of the body is one-fourth of its total energy ?

Two simple harmonic motions of angular frequency 100 and 1000 rad s^-1 have the same displacement amplitude.  The ratio of their maximum accelerations is:

The displacement x (in metres) of a particle performing S.H.M is related to time t (in second) as :

The time period of a simple pendulum is 2 s.  If its length is increased by 4 times, then its period becomes:

A particle moving along the X-axis executes simple harmonic motion; then the force acting on it is given by:

A particle is executing S.H.M of amplitude 4 cm and T = 4 sec.  The time taken by it to move from positive extreme position to half the amplitude is:

A particle is subjected to two mutually perpendicular simple harmonic motions such that is x and y coordinates are given by 


      The path of the particle will be:

A simple pendulum performs simple harmonic motion about x=0 with an amplitude a and time period T.  The speed of the pendulum at will be:

A particle of mass 10 g is executing S.H.M, with an amplitude of 0.5 m and periodic time of second.  The maximum value of force acting on the particle is: