A particle executing simple harmonic motion of amplitude 5 cm has a maximum speed of 31.4 cm/s. The frequency of its oscillation is:
4 Hz
2 Hz
1 Hz
Two springs A and B (kA =3kB )are stretched by the same suspended weight. Then the ratio of work done in stretching is:
1 : 2
1 : 3
1 : 4
2 : 1
If metal bob of a simple pendulum is replaced by a wooden bob, then its time period will:
Increase
Decrease
Remain the same
First increases then decreases
Two simple pendulums having length 0.5 m and 2.0 m are displaced linearly a little at the same time. They will be in the same phase when shorter pendulum completes oscillations equal to:
2
5
3
1
In SHM restoring force is F=-kx, where k is the force constant, x is the displacement and a is the amplitude of motion, then total energy depends upon:
k,a and m
k,x,m
k,a
k,x
In a simple harmonic motion, if the displacement is half of the amplitude, then which part of total energy will be kinetic energy ?
1/3
3/4
2/3
1/4
The particle executing simple harmonic motion has a kinetic energy . The maximum values of the potential energy and the total energy are respectively will be:
0 and 2K0
K0 and 2 K0
K0 and K0
A particle executing S.H.M has amplitude 0.01 m and frequency 60 Hz. The maximum acceleration of the particle is:
A particle is performing simple harmonic motion along the x axis with amplitude 4 cm and time period 1.2 sec. The minimum time taken by the particle to move from x = + 2 cm to x = + 4 cm and back again is:
0.4 s
0.3 s
0.2 s
0.6 s
A body is executing S.H.M When its displacement from the mean position is 4 cm and 5 cm, the corresponding velocities are 10 cm/sec and 8cm/sec. Then the time period of the body is: