When a long spring is stretched by 2 cm., its potential energy is U. If the spring is stretched by 10 cm, the potential energy in it will be:
10U
25U
5U
Frequency of a simple pendulum in a freely falling lift will be:
Zero
Infinite
Finite
can't say
A particle starts S.H.M from the mean position. Its amplitude is A and time period is T. At the time its speed is half of the maximum speed. Its displacement y from the mean position is:
A particle executes simple harmonic motion of amplitude A. At what distance from the mean position its kinetic energy is equal to its potential energy ?
0.51 A
0.61 A
0.71 A
0.81 A
A particle executes simple harmonic oscillation with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is:
A simple pendulum is executing simple harmonic motion with a time period T. If the length of the pendulum is increased by 21%, the increase in the time period is:
21%
10%
30%
50%
Two springs A and B have force constants KA and KB such that kB =2kA. The four ends of the springs are stretched by the same force. If the energy stored in the spring A is E, then the energy stored in spring B will be :
2E
E
4E
Which one of the following is a simple harmonic motion ?
Ball bouncing between two rigid vertical walls
Particle moving in a circle with uniform speed
Wave moving through a string fixed at both ends
Earth spinning about its own axis
A particle is performing simple harmonic motion along the x axis with amplitude 4 cm and time period 1.2 sec. The minimum time taken by the particle to move from x = + 2 cm to x = + 4 cm and back again is:
0.4 s
0.3 s
0.2 s
0.6 s
A point particle of mass 0.1 kg is executing S.H.M of amplitude 0.1 m. When the particle passes through the mean position, its K.E is 8 x 10-3 J. The equation of motion of this particle if its initial phase of oscillations is 45o is:
