A particle moves such that its acceleration a is given by a = -bx where x is the displacement from equilibrium position and b is a constant. The period of oscillations is:
A hollow sphere filled with water forms the bob of a simple pendulum. A small hole at the bottom of the bob allows the water to slowly flow out as it is set into small oscillations and its period of oscillations is measured. The time period will :
Increase
Decrease
Remain constant
First increases , then decreases
The S.H.M. of a particle is given by the equation . The amplitude will be:
7
12
1
5
A particle executing simple harmonic motion of amplitude 5 cm has a maximum speed of 31.4 cm/s. The frequency of its oscillation is:
4 Hz
2 Hz
1 Hz
If a simple harmonic oscillator has got a displacement of 0.02 m and acceleration equal to 2.0m/s2 at any time, the angular frequency of the oscillator is equal to:
10 rad/s
0.1 rad/s
100 rad/s
1 rad/s
A body is vibrating in S.H.M. with an amplitude of 0.06 m and frequency of 15 Hz. The maximum velocity and acceleration of the body are:
5.65 m/s, 5.32 x 102 m/s2
6.82 m/s, 7.62 x 102 m/s2
8.91 m/s, 8.21 x 102 m/s2
9.82 m/s, 9.03 x 102 m/s2
A rectangular block of mass m and the area of cross-section A floats in a liquid of density .If it is given a small vertical displacement from equilibrium it undergoes oscillation with a time period T. Then
The acceleration of a particle in S.H.M. is:
Always constant
Maximum at extreme positions
Maximum at mean position
Always zero
Two springs of constants k1 and k2 have equal maximum velocities when executing simple harmonic motion. The ratio of their amplitudes (the masses are equal) will be:
A body of mass 5 kg hangs from a spring and oscillates with a time period of 2 seconds. If the body is removed, the length of the spring will decrease by:
2 metres
g metres
g/k metres
k/g metres
