A particle moves such that its acceleration a is given by a = -bx where x is the displacement from equilibrium position and b is a constant. The period of oscillations is:
The total energy of a body performing S.H.M. depends on:
k,a,m
k,a,x
k,a
k,x
A particle executing simple harmonic motion of amplitude 5 cm has a maximum speed of 31.4 cm/s. The frequency of its oscillation is:
4 Hz
2 Hz
1 Hz
When a damped harmonic oscillator completes 100 oscillations, its amplitude is reduced to of its initial value. What will be its amplitude when it completes 200 oscillations ?
A body executes SHM with an amplitude . At what displacement from the mean position is the potential energy of the body is one-fourth of its total energy ?
Some other fraction of a
A particle starts S.H.M from the mean position. Its amplitude is A and time period is T. At the time its speed is half of the maximum speed. Its displacement y from the mean position is:
The displacement a of particle between maximum potential energy position and maximum kinetic energy position in simple harmonic motion is:
The kinetic energy of a particle executing S.H.M. is 16 J when it is in its mean position. If the amplitude of oscillations is 25 cm and the mass of the particle is 5.12 kg, the time period of oscillations is:
A particle moving along the X-axis executes simple harmonic motion; then the force acting on it is given by:
-AKx
A cos Kx
A exp(-Kx)
AKx
A particle has simple harmonic motion. Its equation of motion is :cm where x is the displacement. If the displacement of the particle is 3 cm, then its velocity in cm/s is:
20
16
