The total energy of a body performing S.H.M. depends on:
k,a,m
k,a,x
k,a
k,x
If metal bob of a simple pendulum is replaced by a wooden bob, then its time period will:
Increase
Decrease
Remain the same
First increases then decreases
Two springs A and B have force constants KA and KB such that kB =2kA. The four ends of the springs are stretched by the same force. If the energy stored in spring A is E, then the energy stored in spring B will be:
2E
E
4E
The composition of two simple harmonic motions of equal periods at right angle to each other and with a phase difference of results in the displacement of the particle along:
Circle
Figure of eight
Straight line
Ellipse
A particle of mass 200 g executes S.H.M. The restoring force is provided by a spring of force constant 80 N/m. The time period of oscillations is:
0.15 sec
0.02 sec
0.31 sec
0.05 sec
Two simple harmonic motions of angular frequency 100 and 1000 rad s-1 have the same displacement amplitude. The ratio of their maximum accelerations is:
1:10
1:102
1:103
1:104
The S.H.M. of a particle is given by the equation . The amplitude of motion is:
7
12
1
5
The acceleration of a particle in S.H.M. is:
Always constant
Maximum at extreme positions
Maximum at mean position
Always zero
A particle moves such that its acceleration a is given by a = -bx where x is the displacement from equilibrium position and b is a constant. The period of oscillations is:
Frequency of a simple pendulum in a freely falling lift will be :
Zero
Infinite
Finite
can't say
