A pendulum is displaced to an angle from its equilibrium position; then it will pass through its mean position with a velocity v equal to:

A body is vibrating in S.H.M. with an amplitude of 0.06 m and frequency of 15 Hz. The maximum velocity and acceleration of the body are:

A point particle of mass 0.1 kg is executing S.H.M of amplitude 0.1 m.  When the particle passes through the mean position, its K.E is 8 x 10^-3 J.  The equation of motion of this particle if its initial phase of oscillations is 45^o is:

A particle executing simple harmonic motion of amplitude 5 cm hasa  maximum speed of 31.4 cm/s.  The frequency of its oscillation is:

The displacement x (in metres) of a particle performing S.H.M is related to time t (in second) as :

Two springs A and B (k_A =3k_B )are stretched by the same suspended weight.  Then the ratio of work done in stretching is:

The potential energy of a simple harmonic oscillator when the particle is half way to its end point is:

Two simple harmonic motions given by,
act on a particle simultaneously, then the motion of particle will be:

A particle executes simple harmonic oscillation with an amplitude a.  The period of oscillation is T.  The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is:

A particle is executing S.H.M of amplitude 4 cm and T = 4 sec.  The time taken by it to move from positive extreme position to half the amplitude is: