A cylindrical resonance tube open at both ends, has a fundamental frequency ƒ, in air. If half of the length is dipped vertically in water, the fundamental frequency of the air column will be:

Two sound waves with wavelengths 5.0 m and 5.5 m respectively, each propagate in a gas with velocity 330 m/s. We expect the following number of beats per second:

A 5.5 m length of string has a mass of 0.035 kg. If the tension in the string is 77 N, the speed of a wave on the string is:

A standing wave having 3 nodes and 2 anti node is formed between two atoms having a distance 1.21Å between them. The wavelength of the standing wave is:

Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same adn equal to 1 gm^-1. When both the strings vibrate simultaneously the number of beats will be:

A vehicle, with a horn of frequency n is moving with a velocity of 30 m/s in a direction perpendicular to the straight line joining the observer and the vehicle. The observer perceives the sound to have a frequency n + n₁.Then n1 is equal to : ( the sound velocity in air is 300 m/s)

Two trains move towards each other with the same speed. The speed of sound is 340 m/s. If the height of the tone of the whistle of one of them heard on the other changes times, then the speed of each train should be:

A sonometer wire when vibrated in full length has frequency n. Now it is divided by the help of bridges into a number of segments of lengths l₁,l₂,l₃,... When vibrated these segments have frequencies n₁,n₂,n₃,... then the correct relation is:

A plus of wave train travels along a stretched string and reaches the fixed end of the string. It will be reflected back with :

The driver of a car travelling with speed 30 ms-1 towards a hill sounds a horn of frequency 600 Hz. If the velocity of sound in air is 330 ms^-1, the frequency of reflected sound as heard by driver is: