There is an electric field E along x direction.If the work done is moving a charge 0.2c through a distance 2m along a line making an angle 60owith the x axis is 4.The value of E is
4N/C
8N/C
16N/C
20N/C
The energy acquired when an alpha particles is accelerated through a potential difference of 1 volt is
1 ev
2 ev
4 ev
0
Two spherical conductors B and c of equal radii and carrying equal charge on them repel each other with a force F when kept apart at some distance.A third spherical conductor having some redius as that of B but uncharged is brought in contact with B and then with C and removed away from both.The new force of repulsion between B and C
F/4
3F/4
F/8
3F/8
The kinetic energy of an electron accelerated through a potential of 100x is
1.6x10-17 J
1.6x1017 J
1.6x10-19 J
100J
For what purpose Gold leaf electroscope is used?
To find the electric field
To find the electric potential
To detect the charge on a body
To find the force between charges.
An isolated metal sphere of radius R is given a charge q. its potential energy will be
q2/ 4π∈0R
q/ 4π∈0R
q/ 8π∈0R
q2/ 8π∈0R
The electric potential V at a certain point distant x metre from the origin is given by V(x)= (5x2+10x-9) volt. The electric field at x=1m will be
20 v/m
-10 v/m
10 v/m
-20v/m
Two charged balls attract each other with a certain force.If they are allowed to touch and then separated to the same distance appart the two balls will
Attract with smaller force
Attract with greater force.
Repel with smaller force
Repel with greater force.
The unit of electric field is
volt*metre
volt/joule
volt*joule
volt/metre
A parallel plate capacitor is charged by connecting the plates to a battery. The battery remains connected and a glass plate is inserted between the plates of the capacitor then
charge in the capacitor increases
charge in the capacitor decreases
voltage on the capacitor increases
voltage on the capacitor decreases
