Nitrobenzene on further excessive nitration gives
sym - Trinitrobenzene
m - Dinitrobenzene
p - Dinitrobenzene
All of these
Tautomerism will be exhibited by
(CH3)3CNO
(CH3)2NH
R3CNO2
RCH2NO2
Consider the following reaction What is Y?
Acetanilide
Benzanilide
Azobenzene
Hydrazobenzene
Attacking species in nitration of benzene in presence of fuming HNO3 is
SO3
The reagent that reacts with nitromethane to form methylhydroxylamine is
Zn/HCl
Zn/NH4Cl
Zn/NaOH
Sn/HCl
Reduction of nitrobenzene in the presence of Zn / NH4Cl gives
Aniline
N - phenylhydroxylamine
In the reduction of nitrobenzene, which of the following is the intermediate?
C6H5 - N = O
C6H5NH - NHC6H5
C6H5 - N = N - C6H5
O ↑C6H5 - N = N - C6H5
Tertiary nitro compounds do not tautomerise because
There is no double bond
There is no α - hydrogen
Oxygen is more electronegative than hydrogen
All of the above
The major product (70% to 8%) of the reaction between m-dinitrobenzene with NH4HS is