Reduction of nitrobenzene in the presence of Zn / NH4Cl gives
Azobenzene
Aniline
N - phenylhydroxylamine
Hydrazobenzene
In the reduction of nitrobenzene, which of the following is the intermediate?
C6H5 - N = O
C6H5NH - NHC6H5
C6H5 - N = N - C6H5
O ↑C6H5 - N = N - C6H5
The major product (70% to 8%) of the reaction between m-dinitrobenzene with NH4HS is
Tertiary nitro compounds do not tautomerise because
There is no double bond
There is no α - hydrogen
Oxygen is more electronegative than hydrogen
All of the above
Attacking species in nitration of benzene in presence of fuming HNO3 is
SO3
Consider the following reaction What is Y?
Acetanilide
Benzanilide
In the above sequence, Y can be
4 - Nitrochlorobenzene
I - Nitrochlorobenzene
3 - Nitrochlorobenzene
None of the these
Nitrobenzene on further excessive nitration gives
sym - Trinitrobenzene
m - Dinitrobenzene
p - Dinitrobenzene
All of these
The reagent that reacts with nitromethane to form methylhydroxylamine is
Zn/HCl
Zn/NH4Cl
Zn/NaOH
Sn/HCl