A body of weight W, experiences an upthrust R in water. What will be the apparent weight of the body and apparent density of the body when W<R?
Apparent weight = R - W; Apparent density = (1 - ) g cm-3
Apparent weight = W - R; Apparent density = (1000 - ) kg m-3
Apparent weight = W - R; Apparent density = (-1) g cm-3
Apparent weight = Zero; Apparent density = Zero
In case of hydrometer, the density of liquid is equal to:
In case of hydrometer for lighter liquids
its gravity bulb is heavier
the densities of lighter liquids are marked below the density of water.
the density of water is marked at the top of stem.
Its buoyancy bulb is larger
A solid of mass 22 kg is immersed in water. If it looses half of its weight in water, its R.D. will be
1/4
2
1/2
4
The density of ice is 0.918 g cm-3 and that of water is 1.03 g cm-3 . An iceberg floats with a portion of 224 m3 outside the surface of water. The total volume of ice berg is:
1545 m3
2575 m3
2060 m3
1030 m3
A spring balance records a weight of one kgf when a body is suspended from it. When the body is fully immersed ina liquid ,the reading recorded by the spring balance is zero.What is the apparent density of the body ?
0.5 kg m-3
2 kg m-3
0 kg m-3
1 kg m-3
A combination of wood and iron, just floats in the water at room temperature. Explain what you will observe when the water is heated.
The combination will still float with same position.
The combination will float on the surface of the liquid.
The combination will sink.
None of the above.
The centre of gravity and the centre of buoyancy of a floating body in stable equilibrium(i) are always same(ii) are always along a same vertical line
only (i) is true
only (ii) is true
Both (i) and (ii) are correct
Both (i) and (ii) are false
Two metallic spheres of different materials immersed in water experience equal upthrust. Then both the spheres have equal:-
weights in air
densities
masses
volumes
Express the relationship between the C.G.S and S.I units of density.
1 g cm-3 = 10 kg m-3
1 g cm-3= 100 kg m-3
1 g cm-3= 1000 kg m-3
1000 g cm-3 = 1 kg m-3
