If x2 > 4, then
x > 2
| x | > 2
-2 < x < 2
None of these
The set of values of x satisfying the inequalities ( x -1 ) ( x -2 ) < 0 and ( 3x - 7 ) ( 2x - 3 ) > 0 is
(1, 2 )
( 2, 7/3 )
( 1, 7/3 )
( 1, 3/2 )
If a/b < c/d, then
( a/b)2 < (c/d)2
If 3 < | x | < 6, then x belongs to
( - 6, -3 ) U ( 3, 6 )
( - 6, 6 )
( -3, -3 ) U (3, 6 )
If | x | < x , then:
x is a positive real number
x is a non negative real number
There is no x satisfying this inequality
x is a negative real number
x2 -3 |x| + 2 < 0, then x belongs to
( 1,2 )
( -2, -1 )
( -2, -1 ) U ( 1, 2 )
( -3, 5 )
Solution of is
x ∈(4,∞)
x ∈ [4,∞]
x ∈(4,∞]
x ∈ [4,∞)
If x satisfies the inequations 2x - 7 < 11, 3x + 4 < -5, then x lies in the interval
(-∞, -3)
(-∞, 3)
(-∞, 2)
(-∞, ∞)
( x - 1 ) > 0
( x -2 ) > 0
(x - 2 ) < 0
( x - 1 ) > 0 if ( x -2 ) > 0
If a < b then,
a/(-2 ) < b/(-2)
a/2 > b/2
1/a < 1/b
a/-2 > b/-2
