Log 2x > 4, then x belongs to
x > 4
x > 16
x > 8
None of these
If |x| > 5, then
0 < x < 5
x < -5 or x > 5
-5 < x < 5
x > 5
As sinx < x and x< tanx in ( 0,π/2 ), so in the same interval,
Sinx < tanx
Sinx > tanx
sin2 x > tan 2 x
|sinx | > |tanx |
x2 -3 |x| + 2 < 0, then x belongs to
( 1,2 )
( -2, -1 )
( -2, -1 ) U ( 1, 2 )
( -3, 5 )
If a < b then,
a/(-2 ) < b/(-2)
a/2 > b/2
1/a < 1/b
a/-2 > b/-2
If x satisfies the inequations 2x - 7 < 11, 3x + 4 < -5, then x lies in the interval
(-∞, -3)
(-∞, 3)
(-∞, 2)
(-∞, ∞)
|2x -3| < | x + 5 |, then x belongs to :
( 5, 9 )
( -2/3, 8 )
( -8, 2/3 )
The set of values of x satisfying the inequalities ( x -1 ) ( x -2 ) < 0 and ( 3x - 7 ) ( 2x - 3 ) > 0 is
(1, 2 )
( 2, 7/3 )
( 1, 7/3 )
( 1, 3/2 )
If | x | < x , then:
x is a positive real number
x is a non negative real number
There is no x satisfying this inequality
x is a negative real number
Solution of 4x + 5 < 7x + 8 is
(1, ∞)
(-1, ∞)
(2, ∞)
(-2, ∞)
