When two capacitors of capacitance C1 and C2 are connected in series their effective capacitance will be
C1+C2
C1C2/C1+C2
C1+C2/C1C2
C1 / C2
Work done is moving a charge from one point to another in an equipotential surface is
Zero
Infinity
If the distance between the plates of a charged parallel plate capacitor is reduced to half of its original value, the capacity of the capacitor is
Increased two times
Reduced to half of its original value
Increased to 4 times
Remains unaltered
SI Unit of electric potential is
Watt
Volt
Coulomb / joules
Newton/ Coulomb
The supply of an additional charge to a charged capacitor will
Reduce its potential
Increase its potential
Reduce its capacity
Reduce the permittivity of the medium.
A parallel plate capacitor is charged by connecting the plates to a battery. The battery remains connected and a glass plate is inserted between the plates of the capacitor then
charge in the capacitor increases
charge in the capacitor decreases
voltage on the capacitor increases
voltage on the capacitor decreases
Two spherical conductors B and c of equal radii and carrying equal charge on them repel each other with a force F when kept apart at some distance.A third spherical conductor having some radius as that of B but uncharged is brought in contact with B and then with C and removed away from both.The new force of repulsion between B and C
F/4
3F/4
F/8
3F/8
The dimensions of capacitance are
M-1 L-2 T2 I2
M-1 L-1 T2 I2
M-1 L-2 T3 I2
M-1 L-2 T4 I2
A copper slab of thickness d/2 is introduced between the plates of a parallel plate capacitor of plate separation d. If the capacitance of the capacitor without copper slab is c and with copper slab is c', then c '/c is
√2
2
1
1/√2
Which of the following will not alter the capacitance of a parallel plate capacitor ?
Change is the area of the plates
Change is the distance between the plates
Change is the dielectric medium
Change is the charging potential
