SI Unit of electric potential is
Watt
Volt
Coulomb / joules
Newton/ Coulomb
The dimensions of capacitance are
M-1 L-2 T2 I2
M-1 L-1 T2 I2
M-1 L-2 T3 I2
M-1 L-2 T4 I2
Which of the following will not alter the capacitance of a parallel plate capacitor ?
Change is the area of the plates
Change is the distance between the plates
Change is the dielectric medium
Change is the charging potential
When two capacitors of capacitance C1 and C2 are connected in series their effective capacitance will be
C1+C2
C1C2/C1+C2
C1+C2/C1C2
C1 / C2
Work done is moving a charge from one point to another in an equipotential surface is
Zero
Infinity
With the discovery of quarks the basic unit of charge would be
(1/3)e
1e
(1/2)e
(2/3)e
Two charged balls attract each other with a certain force.If they are allowed to touch and then separated to the same distance appart the two balls will
Attract with smaller force
Attract with greater force.
Repel with smaller force
Repel with greater force.
A parallel plate capacitor is charged by connecting the plates to a battery. The battery remains connected and a glass plate is inserted between the plates of the capacitor then
charge in the capacitor increases
charge in the capacitor decreases
voltage on the capacitor increases
voltage on the capacitor decreases
Two conducting spheres of radii 5cm and 3cm are charged so that the electric field on their surface are same. Calculate the ratio of the charges ?
3:5
5:3
9:25
25:9
The electric potential V at a certain point distant x metre from the origin is given by V(x)= (5x2+10x-9) volt. The electric field at x=1m will be :
20 v/m
-10 v/m
10 v/m
-20v/m
