The volume strength of 1.5 N H2O2 solution is
4.8
5.2
8.4
8.8
1.00g of a non- electrolyte solute (molar mass 250g mol-1) was dissolved in 51.2 g of benzene. If the freezing point depression constant, kf of benzene is 5.12 K kg mol-1, the freezing point of benzene will be lowered by.
0.4 K
0. 3 K
0.5 K
0. 2K.
Acetic acid is dissolved in benzene, and the molecular mass is determined from the elevation of boiling point. The molecular mass obtained will be_____________________
60
120
180
30
Molality is the most inconvenient way of expressing concentration because it_______________________.
Has no unit
Is very difficult to find out
Involves difficult calculations
Involves the measurement of weight of liquids
The lowering of vapour pressure of the solvent takes place on dissolving a non-volatile solute because______________________
the surface tension of the solution decreases
the density of the solution increases
the molecules of the solvent on the surface are replaced by the molecules of the solute
the viscosity of the solution increases
The vapour pressure of two liquids P and Q are 80 and 60 torr, respectively. The total vapour pressure of solution obtained by mixing 3 moles of p and 3 mols of Q would be.
140 torr
20 torr
68 torr
72 torr
If a hydrated crystal has vapour pressure greater than that of water vapour in the atmosphere, the crystal is __________________
Hygroscopic
Efflorescent
Deliquescent
Phosphorescent
During osmosis, flow of water through a semi permeable membrane is
From solution having higher concentration only
From both sides of semi-permeable membrane with equal flow rates
From both sides of semi-permeable membrane with unequal flow rates
From solution having lower concentration only
A solution contains non- volatile solute of molecular mass, M2. Which of the following can be used to calculate then molecular mass of solute in terms of osmotic pressure?
Formation of a solution from two components can be considered as
Solution so formed will be ideal, if
ΔHsoln = ΔH1 - ΔH2 - ΔH3
ΔHsoln = ΔH3 - ΔH1 - ΔH2
ΔHsoln = ΔH1 + ΔH2 + ΔH3
ΔHsoln = ΔH1 + ΔH2 - ΔH3
