The equation of bisector of acute angle between lines 3x - 4y + 7 = 0 and 12x + 5y - 2 = 0 is.
21x + 77y - 101 = 0
11x - 3y + 9 = 0
31x + 77y +101 = 0
11x - 3x - 9 = 0
Lines (a - b ) x + (b - c) y + (c - a) = 0, (b - c ) x + (c - a) y + (a - b) = 0, (c - a ) x + (a - b) y + (b - c ) = 0 are
Parallel
Concurrent
Mutually Perpendicular
None of these
The opposite vertices of a square are (1,2) and (3,8) , then equation of diagonal passing through (1,2) is
3x - y - 1 = 0
3x - y + 1 = 0
y + 3x - 1 = 0
y + 3x + 1 = 0
The intersection point of lines and lie on
x - y = 0
(x + y) (a + b) = 2 ab
(x + my) (a + b) = (l + m) ab
The equation of sides of a quadrilateral AB,BC,CD, and DA are x + 2y = 3, x = 1, x - 3y = 4,5x + y + 12 = 0, the angle between diagonals AC and AD is
If a point p is at a distance of 5 units on one of the lines y - √3 | x | = 2 from their intersection point, then the foot of perpendicular drawn from p on the bisector of the angle between lines is
(It depends on that the point p lies on which line)
The coordinates of foot of perpendicular from origin to the line 3x+4y -5 = 0 is
Line L is perpendicular to line 5x - y = 1.The area of triangle formed by coordinates axis and line is 5 sq . units.Then its equation is
x + y = √2
x + 5y = ± 5 √2
x + 5y = -5
x + 5y = - √2
The angle between lines 3x + y - 7 = 0 and x + 2y + 9 = 0 is
120o
135o
180o
90o
The ortho centre of the triangle formed by vertices (0,0) , (8,0) and (4,6) is
(3,4)
(4,3)
(-3,4)
(4, 8/3)
