If ar (ΔABC) = ar (ΔDBC), then which of the following is always true?
AD || BC
Area (AOD) = area (BOC)
∠AOD = 90°
AB > DC
ABCD is a trapezium with AB||CD. If AL⊥DC, AB = 5cm, DC = 10cm and area (trapezium ABCD) = 45cm2. Then h =
6cm
9 cm
12cm
3cm
ABCD is ||gm. O is an interior point. If area (ΔAOB) + area (ΔDOC) = 43. sq. units. Then area (||gm ABCD) =
172 sq.units
123 sq.units
143 sq.units
86 sq.units
In the figure ABCD is a parallelogram and AEB is a triangle. If ar ||gm ABCD = 172.6 sq.cm Then ar ΔAEB =
86.3 sq.cm
172.6 sq.cm
354.2 sq.cm
Cannot be determined
Which of the following statement is correct.
Area (ABCD) = area (ABCDE)
Area (ABCD) = area (BCDE)
Area (ABDE) = area (BCD)
None of these
P is the midpoint of side AB of ||gm ABCD. If area ||gm ABCD = 96 sq.units, then area ΔAPQ =
48 sq.units
72 sq.unit
24 sq.unit
198 sq.unit
Which of the following figures show quadrilateral and a triangle on same base and between same parallels?
In the given figure, D is midpoint of ΔABC. If ar ΔABC = (2x2 - 2)units, then ar ΔABD =
(x - 1)2
(x + 1)2
2(x - 1) (x + 1)
(x + 1) (x - 1)
If D is midpoint of BC and area ΔABD = 1/√2 sq.units, then area ΔABC is
1/√2 sq. units
√2 sq. units
2 sq.unit
ABCD is a ||gm E,F,G and H are mid point of AB, BC, CD and DA respectively. If area (EFGH) = 73 sq. unit. Then area (||gm ABCD) =
36.5 sq.units
73 sq. unit
146 sq. unit
292 sq. unit
