Which of the following transitions gives photon of maximum energy ?
n = 1 to n = 2
n = 2 to n = 1
n = 2 to n = 6
n = 6 to n = 2
Hydrogen atoms are excited from ground state of the principal quantum number 4. Then the number of spectral lines observed will be
3
6
5
2
In terms of Bohr radius α0, the radius of the second Bohr orbit of a hydrogen atom is :
4 α0
8 α0
√ 2 α0
2 α0
The radius of hydrogen atom in its ground state is 5.3 x 10 -11 m. After collision with an electron it is found to have a radius of 21.2 x 10 – 11 m. What is the principal quantum number n of the final state of the atom ?
n = 4
n = 2
n = 16
n = 3
The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is
3.4 eV
6.8 eV
10.2 eV
Zero
Energy E of a hydrogen atom with principal quantum number n is given by .The energy of a photon ejected when the electron jumps from n = 3 state to n = 2 state of hydrogen,is approximately
1.5 eV
0. 85 eV
1.9 eV
Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr’s theory, the spectral lines emitted by hydrogen will be :
4
1
In a Rutherford scattering experiment when a projectile of charge Z1 and mass M1 approaches a target nucleus of charge Z2 and mass M2, the distance of closest approach is r0. The energy of the projectile is :
directly proportional to M1 x M2
directly proportional to Z1 Z2
inversely proportional to Z1
directly proportional to mass M1.
When electron jumps from n = 4 to n = 2 orbit, we get :
second line of Lyman series
second line of Balmer series
second line of Paschen series
an absorption line of Balmer series
The total energy of an electron in the first excited state of hydrogen is about – 3.4 eV. Its kinetic energy in this state is
-3.4 eV
- 6.8 e V
