Hydrogen atoms are excited from ground state of the principal quantum number 4. Then the number of spectral lines observed will be
3
6
5
2
The ionization energy of hydrogen atom is 13.6 eV,What will be the ionization energy of helium atom ?
13.6 eV
27.2 eV
6.8 eV
54.4 eV
The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is
3.4 eV
10.2 eV
Zero
When a hydrogen atom is raised from the ground state to an excited state.
PE decreases and KE increases
PE increases and KE decreases
Both KE and PE decreases
Absorption spectrum
Energy levels A, B, C, of a certain atom correspond to increasing values of energy ie, EA < EB < EC, If λ1, λ2, λ3 are the wavelengths of radiation corresponding to the transitions C to B, B to A and C to A respectively, which of the following relation is correct ?
λ3 = λ1 +λ2
λ3 = λ1 λ2/λ1 +λ2
λ1 +λ2 + λ3 = 0
λ23 = λ21 +λ22
In Rutherford scattering experiment, what will be the correct angle for α- scattering for an impact parameter, b = 0 ?
90o
270 o
0o
180o
Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr’s theory, the spectral lines emitted by hydrogen will be :
4
1
Bohr's model is based on :
Conservation of linear momentum
Conservation of angular momentum
Conservation of quantum frequency
Conservation of energy
Which source is associated with a line emission spectrum ?
Electric fire
Neon street sign
Red traffic light
Sun
The radius of hydrogen atom in its ground state is 5.3 x 10 -11 m. After collision with an electron it is found to have a radius of 21.2 x 10 – 11 m. What is the principal quantum number n of the final state of the atom ?
n = 4
n = 2
n = 16
n = 3
