Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state are excited by monochromatic radiation of photon energy 12.1 eV. According to Bohr’s theory, the spectral lines emitted by hydrogen will be :
2
3
4
1
Energy E of a hydrogen atom with principal quantum number n is given by .The energy of a photon ejected when the electron jumps from n = 3 state to n = 2 state of hydrogen,is approximately
1.5 eV
0. 85 eV
3.4 eV
1.9 eV
The spectrum obtained from a sodium vapour lamp is an example of
band spectrum
continuous spectrum
emission spectrum
absorption spectrum
The ground state energy of hydrogen atom is -13.6 eV. When its electron is in the first excited state, its excitation energy is
6.8 eV
10.2 eV
Zero
Which of the following transitions gives photon of maximum energy ?
n = 1 to n = 2
n = 2 to n = 1
n = 2 to n = 6
n = 6 to n = 2
Hydrogen atoms are excited from ground state of the principal quantum number 4. Then the number of spectral lines observed will be
6
5
Bohr's model is based on :
Conservation of linear momentum
Conservation of angular momentum
Conservation of quantum frequency
Conservation of energy
Which source is associated with a line emission spectrum ?
Electric fire
Neon street sign
Red traffic light
Sun
The valence electron in alkali metal is a
f – electron
p – electron
s – electron
d – electron
The ionization energy of hydrogen atom is 13.6 eV,What will be the ionization energy of helium atom ?
13.6 eV
27.2 eV
54.4 eV
