The equation of lines passing through (3,2) and perpendicular to y = x is.
x - y = 5
x + y = 5
x + y = 1
x - y =1
If P is the length of perpendicular from origin to the line which intercepts a and b on axes , then.
a2 + b2 = p2
a2 + b2 = 1/p2
1/a2 + 1/b2 = 2/p2
1/a2 + 1/b2 = 1/p2
If line passing through (4,3) and (2,k) is perpendicular to y = 2x + 3 then k =
-1
1
-4
4
If lines 3x - 4y - 13 = 0,8x - 11y - 33 = 0 and 2x - 3y + λ = 0 are concurrent , λ =
7
-7
5
-5
If lines x + 2ay + a = 0, x + 3by + b = 0 and x + 4cy + c = 0 are concurrent,then a,b,c, are in
A.P
G.P
H.P
None of these
The vertices of any traingle are (2,1) (5,2) and (4,4) , the length of perpendicular drawn from vertices on opposite sides are.
The coordinates of foot of perpendicular from origin to the line 3x+4y -5 = 0 is
The equation of line which passes through (1,-2) and cuts equal intercepts with coordinate axis is.
x - y = 1
x + y + 1 = 0
x - y - 2 = 0
The angle between lines y = (2 - √3) x + 5 and y = (2 + √3) x - 7 is.
30o
45o
-60o
90o
Lines a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0 will be mutually perpendicular if.
a1 b2 - b1 a2 = 0
a1 a2 + b1 b2 = 0
a12 b2 + b12 a2 = 0
a1 b1 + a2 b2 = 0