If lines 3x - y =2,5x + ay = 3 and 2x + y = 3 are concurrent ,then a =
2
3
-1
-2
A straight line makes angle 135o with x - axis and cut y - axis at distance -5 from origin.The equation of line is.
2x + y + 5 = 0
x + 2y + 3 = 0
x + y + 5 = 0
x + y + z = 0
If lines 3x - 4y - 13 = 0,8x - 11y - 33 = 0 and 2x - 3y + λ = 0 are concurrent , λ =
7
-7
5
-5
If P (a,b) lies on 3x + 2y = 13 and point Q (b,a) lies on 4x - y = 5 then the equation of PQ is
x - y = 5
x + y = 5
x + y = -5
x - y = -5
If lines x + 2ay + a = 0, x + 3by + b = 0 and x + 4cy + c = 0 are concurrent,then a,b,c, are in
A.P
G.P
H.P
None of these
If line passing through (4,3) and (2,k) is perpendicular to y = 2x + 3 then k =
1
-4
4
Lines a1x + b1y + c1 = 0 and a2x + b2y + c2 = 0 will be mutually perpendicular if.
a1 b2 - b1 a2 = 0
a1 a2 + b1 b2 = 0
a12 b2 + b12 a2 = 0
a1 b1 + a2 b2 = 0
The vertices of any traingle are (2,1) (5,2) and (4,4) , the length of perpendicular drawn from vertices on opposite sides are.
The equation of bisector of obtuse angle of x - 2y + 4 = 0 and 4x - 3y + 2 = 0 is.
(4 - √5 ) x - (3 - 2 √5) y + (2 - 4 √5 ) = 0
(4 + √5) x + (3 - 2 √5 )y + (2 - 4 √5) = 0
(4 - √5) x + (3 + 2 √5) y + (2 - 4 √5) = 0
(4 - √5) x - (3 + 2 √5 ) y - (2 - 4 √5 ) = 0
The coordinates of foot of perpendicular from origin to the line 3x+4y -5 = 0 is
