Diameter of human eye lens is 2mm. What will be the minimum distance between two points to resolve them, which are situated at a distance of 50m from eye? [The wavelength of light is 5000 Å]
2.32 m
4.28 mm
1.25 cm
12.48 cm
If fv and fn are the focal lengths of a convex lens for violet ad red light respectively and FV and FR are the focal lengths of concave lens for violet and red light respectively, then we have
fV < fR and FV > FR
fV < fR and FV < FR
fV > fR and FV > FR
fV > fR and FV < FR
Focal length of a convex lens of refractive index 1.5 is 2 cm. Focal length of lens when immersed in a liquid of refractive index of 1.25 will be
10cm
2.5 cm
5 cm
7.5 cm
A body is located on a wall. Its image of equal size is to be obtained on a parallel wall with the help of a convex lens. The lens is placed at a distance d ahead of second wall, then the required focal length will be :
more than but less than
less than
A convex lens is dipped in a liquid whose refractive index is equal to the refractive index of the lens. Then its focal length will
become small, but non-zero
remain unchanged
become zero
become infinite
Which of the following phenomenon is not explained by Huygen's construction of wavefront?
Refraction
Reflection
Diffraction
Origin of spectra
Interference is possible in
light waves only
sound waves only
Both light and sound waves
Neither light nor sound waves
Electromagnetic radiation of frequency v frequency, velocity v and wavelength λ, in air enters a glass slab of refracive index μ. The frequency, wavelength and velocity of light in the glass slab will be, respectively
The angular resolution of a 10 cm diameter telescope at a walength of 5000 Å is of the order of
106 rad
10-2 rad
10-4 rad
10-6 rad
A lens is placed between a source of light and a wall. It forms images of area A1 and A2 on the wall, for its two different positions, the area of the source of light is