A planoconvex lens is made of a material of refractive index μ = 1.5. The radius of curvature of curved surface of the lens is 20 cm. If its plane surface is silvered, the focal length of the silvered lens will be :
10 cm
20 cm
40 cm
80 cm
Electromagnetic radiation of frequency v frequency, velocity v and wavelength λ, in air enters a glass slab of refracive index μ. The frequency, wavelength and velocity of light in the glass slab will be, respectively
If fv and fn are the focal lengths of a convex lens for violet ad red light respectively and FV and FR are the focal lengths of concave lens for violet and red light respectively, then we have
fV < fR and FV > FR
fV < fR and FV < FR
fV > fR and FV > FR
fV > fR and FV < FR
Diameter of human eye lens is 2mm. What will be the minimum distance between two points to resolve them, which are situated at a distance of 50m from eye? [The wavelength of light is 5000 Å]
2.32 m
4.28 mm
1.25 cm
12.48 cm
For the given incident ray as shown in figure, the condition of total internal reflection of the ray will be satisfied if the refractive index of block will be
A transparent cube contains a small air bubble. Its apparent distance is 2 cm when seen through one face and 5 cm when seen through other face. If the refractive index of the material of the cube is 1.5, the real length of the edge of cube must be :
7 cm
7.5 cm
10.5cm
Focal length of a convex lens of refractive index 1.5 is 2 cm. Focal length of lens when immersed in a liquid of refractive index of 1.25 will be
10cm
2.5 cm
5 cm
A convex lens and a concave lens, each having same focal length of 25 cm, are put in contact to form a combination of lenses. The power in diopters of the combination is :
25
50
infinite
zero
The focal lengths of a converging lens measured for violet, green and red colours are fV,fG,fR respectively. We will find
fG > fR
fV < fR
fV > fR
fV = fR
Rainbows are formed by
reflection and diffraction
refraction and scattering
dispersion and total internal reflection
interference only