In figure two line segments AC and BD intersect each other at a point P such that PA = 6 cm, PB = 3 cm, PC = 2.5 cm, PD = 5 cm, ∠APB = 50° and ∠CDP = 30°. Then ∠PBA is equal to

The areas of two similar triangles are 81 cm² and 49 cm² respectively. If the altitude of the first triangle is 6.3 cm then the corresponding altitude of the other is.

If ABC is an acute angled triangle, acute angled at B and AD ⊥ BC, then AC² = 

In figure PQ = 24 cm, QR = 26 cm, ∠PAR = 90^o, PA = 6 cm and AR = 8 cm. The value of ∠QPR is.

ABC and BDE are two equilateral triangles such that D is the midpoint of BC. Ratio of the areas of triangles ABC and BDE is.

In given figure DE || BC and ^AD/_DB = ³/₅.  If AC = 4.8 cm, Find AE.

If two polygons are similar then their sides are

In ΔABC and ΔDEF, ∠B = ∠E, ∠F = ∠C and AB = 2DE, then two triangles are

If ratio of areas of two similar triangle is 9 : 16 then ratio of their medians is

In figure, DE || BC, AD = 2cm, BD = 2.5 cm,  AE = 3.2 cm. Determine AC.