The areas of two similar triangles are 81 cm² and 49 cm² respectively. If the altitude of the first triangle is 6.3 cm then the corresponding altitude of the other is.

ABC and BDE are two equilateral triangles such that D is the midpoint of BC. Ratio of the areas of triangles ABC and BDE is.

The areas of two similar triangles are respectively 9 cm² and 16 cm².  The ratio of their corresponding side is

In a triangle ABC, AB = 3.9 cm, AC = 5.2 cm and the bisector of ∠A meets BC at D. If DC = 2.8 cm, then find BD.

If ABC is an acute angled triangle, acute angled at B and AD ⊥ BC, then AC² = 

In figure, DE || BC, AD = 2cm, BD = 2.5 cm,  AE = 3.2 cm. Determine AC.

ΔABC is such that AB = 3cm, BC = 2 cm and CA = 2.5 cm.  If ΔDEF ~ ΔABC and EF = 4 cm, then perimeter of
ΔDEF is 

A ladder 10 cm long reaches a windows 8 cm above the ground. The distance of the foot of the ladder from base of the

wall is,

If ratio of areas of two similar triangle is 9 : 16 then ratio of their medians is

Two poles of height 6 m and 11 m stand on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.