ABC and BDE are two equilateral triangles such that D is the midpoint of BC. Ratio of the areas of triangles ABC and BDE is.

If ABC is an acute angled triangle, acute angled at B and AD ⊥ BC, then AC² = 

In ΔABC and ΔDEF, ∠B = ∠E, ∠F = ∠C and AB = 2DE, then two triangles are

A ladder 10 cm long reaches a windows 8 cm above the ground. The distance of the foot of the ladder from base of the

wall is,

In figure PQ = 24 cm, QR = 26 cm, ∠PAR = 90^o, PA = 6 cm and AR = 8 cm. The value of ∠QPR is.

The areas of two similar triangles are 121 cm² and 64 cm² respectively. If the median of the first triangle is 12.1 cm, the corresponding median of the other is

The areas of two similar triangles are respectively 9 cm² and 16 cm².  The ratio of their corresponding side is

ΔABC is such that AB = 3cm, BC = 2 cm and CA = 2.5 cm.  If ΔDEF ~ ΔABC and EF = 4 cm, then perimeter of
ΔDEF is 

Two poles of height 6 m and 11 m stand on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.

The areas of two similar triangles are 81 cm² and 49 cm² respectively. If the altitude of the first triangle is 6.3 cm then the corresponding altitude of the other is.