The equation to the straight line passing through the points (4,-5,-2) and (-1,5,3) is
x-4/1=y+5/-2=z+2/-1
x+4/1=y-5/2=z-3/-1
x/-1=y/5=z/3
x/4=y/-5=z/-2
The intercept of the plane 5 x - 3 y + 6 z = 60 on the co-ordinate axes are
(10,20,-10)
(10,-20,12)
(12,-20,10)
(12,20,-10)
The value of aa' + bb'+ cc' being negative .The origin will lie in the acute angle between the planes are +by+cz+d=0 and a ' x + b ' y + c 'z+d '= 0,if
a = a' = 0
d and d' are of same sign
d and d' are of opposite sign
None of these
A variable plane moves ,so that the sum of the reciprocals of its intercepts on the co-ordinate axes is 1/2.Then the plane passes through .
(1/2,1/2,1/2)
(-1,1,1)
(2,2,2)
(0,0,0)
The points A (4,5,1), B (0,-1,-1) (3,9,4) and D (-4,4,4) are:
Collinear
Coplanar
Non - coplanar
non collinear and non coplanar
If a line lies in the octant OXYZ and it makes equal angles with the axes ,then
l=m=n=1/√3
l=m=n=±1/√3
l=m=n=-1/√3
l=m=n=±1/√2
The length of the perpendicular from the origin to the plane 3x+4y+12z = 5z is
3
-4
5
The projection of the line joining the points (3,4,5) and (4,6,3) on the line joining the points (-1,2,4) and (1,0,5) is :
4/3
2/3
-4/3
1/2
If a plane meets the coordinate axes at A,B and C such that the centroid of the triangle is (1,2,4), then the equation of the plane is
x + 2 y + 4 z = 12
4 x + 2 y + z = 12
x + 2 y + 4 z = 3
4 x + 2 y + z = 3
The perpendicular distance of the point (6,5,8) from y-axis is
5 units
6 units
8 units
10 units
