If loga[1 + logb {1 + logc x}] = 0, then x =
1
0
abc
a/bc
8log25 =
125
120
64
32
log3(1 + 1/3) + log3 (1 + 1/4) + ......log3 (1 + 1/80) =
2
3
The logarithmic form of 95/2 = 243 is
log2 9 = 243
log9 243 = 5/2
log5 2 = 243
None of these
Exponential form of log6 216 = 3 is
36 = 216
63 = 216
318 = 216
618 = 216
If 0 < a < 1 and x > y then logax __________ logay
<
>
≤
≥
If loga √2 = 1/6, then a
6
4
8
The exponential form of log1/3 1/27 = 3 is
(1/3)3 = 27
(1/27)3 = 1/3
(1/3)3 = 1/27
log2 40 - log25 =
The logarithm of 5832 to the base 3√2 is
5
18
7
