Let f(x) = 1 + x, 0 ≤ x ≤ 2 = 3 - x, for 2 and g(x) = f[f(x)] =
g(x) = 2 + x, 0 ≤ x ≤ 1 = 2 - x, 1 < x ≤ 2 = 4 - x, 2 < x ≤ 3
g(x) = 2 - x2, 0 < x < 2 = 4 - x, 2 < x ≤ 3
g(x) = 2 + x, 0 ≤ x ≤ 2 = 4 + x, 2 < x ≤ 3
None of these
f(a2)
f(a)
f(a+1)
Noneof these
The period of f(x) = sin4x + cos4x is
π
2π
π/2
4π
The inverse function of f(x) = [1 - (x - 5)3]1/5 is
5 + (1 - x5)1/3
5 - (1 - x2)1/3
-5 + (1 - x5)1/3
If A = {4,5,7} B = { 2,4} and C = {2,3,7} then (A-B) x(A-C) =
{(5,4) (5,5) (7,4) (7,5)}
{(5,5) (5,6) (7,5) (7,6)}
{(4,5) (5,5) (7,3) (7,7)}
None
The period of cos(x)2 is
4π2
π2/4
The domain of sin-1 [log3(x/3)] is
(1,9)
(-1,9)
(-9,1)
(-9,-1)
The domain of the function f(x) = log |4 - x2| is
(-2, 2)
R - {2, -2}
R
{-2, 2}
The two linear functions which map [-1, 1] on [0,2] are
y = x + 1, y = 1 - x
y = x - 1, -1 - x
y = 1 + 1/x
y = x, y = -x
Given f: N→N, If f={(1,3) (2,5) (3,7).........} then f(x)=
2x + 1
2x - 1
x + 1
x - 1
