If f(x) = x2 - 1/x2, f(x) =
-f(1/x)
f(1/x)
-f(x)
f(x2)
Given f: N→N, If f={(1,3) (2,5) (3,7).........} then f(x)=
2x + 1
2x - 1
x + 1
x - 1
The period of f(x) = sin 4x + tan 2x is
2π
π
π/2
None of these
Cot θ
- Cot θ
-tan θ
- sin θ
Which of the following function identical?
f(x) = x/x and ∅ (x) = 1
f(x) = logx2 and ∅ (x0 = 2 log x
f(x) = 1 and ∅ (x) = sin2 x + cos2 x
f(x) = x and ∅(x) = (√x)2
The domain of sin-1 [log3(x/3)] is
(1,9)
(-1,9)
(-9,1)
(-9,-1)
The inverse function of f(x) = [1 - (x - 5)3]1/5 is
5 + (1 - x5)1/3
5 - (1 - x2)1/3
-5 + (1 - x5)1/3
Let f(x) = 1 + x, 0 ≤ x ≤ 2 = 3 - x, for 2 and g(x) = f[f(x)] =
g(x) = 2 + x, 0 ≤ x ≤ 1 = 2 - x, 1 < x ≤ 2 = 4 - x, 2 < x ≤ 3
g(x) = 2 - x2, 0 < x < 2 = 4 - x, 2 < x ≤ 3
g(x) = 2 + x, 0 ≤ x ≤ 2 = 4 + x, 2 < x ≤ 3
The two linear functions which map [-1, 1] on [0,2] are
y = x + 1, y = 1 - x
y = x - 1, -1 - x
y = 1 + 1/x
y = x, y = -x
The domain of the function f(x) = log |4 - x2| is
(-2, 2)
R - {2, -2}
R
{-2, 2}
