A true breeding tall and smooth -seeded pea plant is crossed with a true breeding dwarf and wrinkled-seeded plant. The fact that F1 plants were all tall demonstrates:
Principle of assortment of characters
That recombination of characters appears in F2 generation
That P1 tall plants were heterozygous
That tallness was dominant to dwarfness
How many genes a child receives from its father?
25%
50%
75%
100%
If a tall plant is crossed with a dwarf plant, this type of cross is called:
Dihybrid
Monohybrid
Reciprocal
Trihybrid
A family of five daughters only is expecting sixth issue. The chance of its being a son is
Zero
Which one is a hereditary disease?
Cataract
Leprosy
Blindness
Phenylketonuria
Both husband and wife have normal vision though their fathers were colourblind. The probability of their daughter becoming colourblind is
0%
RR (red) is crossed with rr (white). All the Rr offsprings are pink. This is an indication that R gene is:
Hybrid
Recessive
Incompletely dominant
Mutant
Law of independent assortment can be proved on the basis of which of the following ratios:
3 : 1
2 : 1 : 1
9 : 3 : 3 : 1
2 : 1
Haploid are able to express both recessive and dominant alleles/mutations because there are
Many alleles for each gene
Two alleles for each gene
Only one allele for each gene in the individual
Only one allele in a gene
