then f (x) is divisible by
n2 + n
(n + 1)!
(n + 2)!
n! (n2 + n + 1)
Which one of the following determinants has its value as zero?
The value of is
20
-2
0
5
abc
(a + b) (b + c) (c + a)
4 abc
None of these
2 i + 12
2 i - 12
-2 i - 12
-2 i + 12
a + b + c - 3 abc
3 (a + b) (b + c) (c + a)
(a - b) (b - c) (c - a)
(a - b) (b - c) (c - a) (a + b + c)
The value of the determinant is
1
∞
ω
a + b +c
If each entry in any row, or each entry in any column of a determinant is 0, then the value of the determinant is equal to
3
-1
, then x equals
1, 1, 0
0, -1, 1
1, -1, 3
0, 0, 3
