then f (x) is divisible by
n2 + n
(n + 1)!
(n + 2)!
n! (n2 + n + 1)
Δ = 0
Δ = 2 abc
Δ = -abc
Δ = a2 + b2 + c2
If the vertices of a triangle are (-2, -3) and (3, 2) (-1, -8) then area of the triangle.
40cm2
30cm2
15cm2
45cm2
The value of the determinant is
0
1
(a - b) (b - c) (c - a)
None of these
Which one of the following determinants has its value as zero?
The value of is
2 i + 12
2 i - 12
-2 i - 12
-2 i + 12
a + b + c
abc
If 1, ω , ω2 are the cube roots of unity, then
ω
ω2
, then
α = 1
α = 0
α = -1
