Which one of the following determinants has its value as zero?
[2, 3]
[3, 4]
[2, 4]
(2, 4)
, then x equals
1, 1, 0
0, -1, 1
1, -1, 3
0, 0, 3
The value of the determinant is
0
1
(a - b) (b - c) (c - a)
None of these
then f (x) is divisible by
n2 + n
(n + 1)!
(n + 2)!
n! (n2 + n + 1)
The value of is
abc
(a + b) (b + c) (c + a)
4 abc
, then
Δ = 0
Δ = 2 abc
Δ = -abc
Δ = a2 + b2 + c2
a + b +c
2 Δ
3 Δ
6 Δ
If each entry in any row, or each entry in any column of a determinant is 0, then the value of the determinant is equal to
3
-1
