(1 + tan2θ) Sin2θ =
Sin2θ
Cos2θ
tan2θ
Cot2θ
2 Cos θ
2 Sec θ
2 Sin θ
Cos4x - Sin4x =
2Sin2x - 1
2Cos2x - 1
1+ 2sin2x
1 - 2Cos2x
9 tan2θ - 9 Sec2θ =
1
0
9
-9
In the adjoining figure
45°
30°
60°
50°
13
25
(Cosec A - Sin A) (Sec A - Cos A) (tan A + Cot A) =
Sin A
Cos A
If Cosθ = Sin θ, then θ =
30
60
45
35
If Cos θ = , then Sin θ is equal
