9 tan2θ - 9 Sec2θ =
1
0
9
-9
Sin (90 - θ) Cos θ + Cos (90 - θ) Sinθ =
2
-1
Sin (90 - θ). Cos( 90 - θ)
tan θ
Cot θ
If Cos θ = , then Sin θ is equal
In the adjoining figure, AC = ________
25 m
(Cos2θ - 1) (Cot2θ + 1) + 1 =
In the adjoining figure, Sinθ = . Then BC =
85 m
65 m
95 m
15 m
(1- Sin2θ) Sec2θ
tan2θ
Cos2θ
