The maximum and minimum value of 3x4-8x3+12x2-48x+1 on the interval [1,4] is
257,-63
-257,63
-63,-63
-40,-40
Let f (x) satisfy the requirements of Lagrange's Mean Value Theorem in [0, 2].If f (0) = 0 and | f' (x) | ≤ 1/2 for all x in [0, 2], then
f (x) ≤ 2
| f (x) | ≤ 1
f (x) = 2x
f (x) = 3 for at least one x in [0, 2]
If a differentiable function f (x) has a relative minimum at x = 0, then the function y = f i.e. y = f (x) + ax + b has a relative minimum at x = 0 for
all a and all b
all b if a = 0
all b > 0
all a > 0
For f (x) = (x - 1)2/3, the mean value theorem is applicable in the interval
(1, 2)
(0, 2)
Any finite interval
None of these
Two towns A and B are 60 Km apart.A school is to be built to serve 150 students in town A and 50 students in town B.If the total distance to be travelled by all 200 students is to be as small as possible, then the school should be built at
Town B
45 km. from town A
Town A
45 km. from town B
The least value of a such that the function x2+ax+1 is increasing on (1,2) is
2
-2
1
-1
Minimum value of f (x) = sin x in - π/2 ≤ x ≤ π/2 is
0
If x be real the minimum value of x2 - 8x + 17 is
The two positive numbers whose sum is 16 and the sum of whose cubes is minimum
8,7
6,8
8,8
8,6
f (x) = 1 + [cos x] x, in 0 < x ≤ π/2
is continuous in [0, π/2]
has a maximum value 2
has a minimum value 0
is not differentiable at x = π/2