A angle between a line is given by
The vector equation of a plane at a distance 6 units from the origin and has as the unit vector normal to it is
The direction cosines of the perpendicular from the origin to the plane are
2, -3, -6
-2, 3, 6
-2/7, 3/7,6/7
2/7, -3/7, -6/7
The distance from p(2, 1, -1) to the plane x - 2y + 4z = 9 is
13/√21
-13/√21
9/√21
-9/√21
The direction cosines of the normal to the plane 2x - 3y + 6z = 7 are
1/7, 1/7, 1/7
2/7, -3/7, 6/7
-2/7, 3/7, -6/7
-1/7, -1/7, -1/7
The equation of any plane is of __________ degree in x, y and z
First
Second
Third
Zero
The equation of the plane passing through he origin and containing the line is
x + 5y - 3z = 0
x - 5y + 3z = 0
x - 5y - 3z = 0
x + 5y + 3z = 0
The equation of the plane through (0, 1, -2) parallel to the plane 2x - 3y + 4z = 0. is
3x - 2y - 4z = 0
3x - 2y + 4z = 0
2x - 3y + 4z = -11
2x - 3y + 4z = 0
If from a point p(a, b, c) perpendicular PA, PB are drawn to yz and zx plane, then the equation of the plane oAB is
bcx = cay + abz = 0
bcx + cay - abz = 0
bcx - cay + abz = 0
-bcx + cay + abz = 0
The angle between the planes 2x - y + 2z = 3 and 3x + 6y + 2z = 4 is
cos-1 5/21
cos-1 4/21
cos-1 3/21
cos-1 2/21
