Air has a refractive index 1.0003. The thickness of air column, which will have one more wavelength of yellow light (6000 Å) than in the same thickness in vacuum is
2 mm
2 cm
2 m
2 km
Two points separated by a distance of 0.1 mm can just be inspected in a microscope when light of wavelength 6000 Å is used. If the light of wavelength 4800 Å is used, this limit of resolution will become
0.80 mm
0.12 mm
0.10 mm
0.08 mm
A beam of ordinary unpolarised light passes through a tourmaline crystal C1 and then it passes through another tourmaline crystal C2 which is oriented such that its principle plane is parallel to that of C2. The intensity of emergent light is I0. Now, C2 is rotated by 60o about the ray. The emergent ray will have an intensity
2 I0
I0 / 2
I0 / 4
I0 / √2
Light appears to travel in a straight line because
wavelength of light is vey small
frequency of light is very small
light consists of very small particles
velocity is different for different colours
In Young's double slit experiment, the seventh maximum with wavelength λ1 is at a distance d1 and the same maximum with wavelength λ2 is a distance d2. Then d1/d2
Two coherent light sources S1 and S2 (λ = 6000 Å) are 1 mm apart from each other. The screen is placed at a distance of 25 cm from the sources. The width of the fringes on the screen should be
0.015 cm
0.025 cm
0.010 cm
0.030 cm
λa and λm are the wavelengths of a beam of light in air and in a medium respectively. If θ is the polarising angle, the correct relation between λa , λm and θ is
λa = λm tan2 θ
λm = λa tan2 θ
λa = λm cot θ
λm = λa cot θ
In Young's double slit experiment, let S1 and S2 be the two slits, and C be the centre of the screen. If∠S1CS2 = θ and λ is the wavelength, the fringe width will be
λ/θ
λ θ
In a Young's double slit experiment the intensity at a point where the path difference is λ/6 (λ being the wavelength of the light used) is I. If I0 denotes the maximum intensity. I/I0 is equal to
1/√2
√3/2
1/2
3/4
The Young's double slit experiment is performed with blue and with green light of wavelengths 4360 Å and 5460 Å respectively. If x is the distance of the 4th maxima from the central one, then
x(blue) = x(green)
x(blue) > x(green)
x(blue) < x(green)
x(blue) / x(green) = 5460/4360