sin θ × _______ = 1
cos θ
cosec θ
sec θ
cot θ
cosec 74 + tan 81 equal to
sec18 + cot 10
sec17+ cot 11
sec16 + cot 9
sec19+ cot 12
If 2 sin θ = √3, then cos θ =
√3/2
2/√3
1/2
2
sin2 50+ cos2 50 =
1
0
1.25
2.32
In right triangle Δ ABC, ∠ B = 90o, tan C = 1/2. If AC = 6 cm, then AB =
6/√5 cm
2 cm
3/√5 cm
√5 cm
In the figure find sin (90o - θ )
4/5
3/5
5/3
5/4
Which of the following relation is true?
cot θ =
cos θ/ sinθ
1/cos θ
sin θ/cosθ
1/sec θ
If sec θ = 2 then sin θ =
3/2
1/√3
If a sin θ = 1 and b tan θ = 1, then the relation between a and b is
a2 = b2
a2 - b2 = 1
a2 + b2 = 1
a2 + b2 = -1
