In the figure find sin (90o - θ )
4/5
3/5
5/3
5/4
1/5
1/3
If 2 sin θ = √3, then cos θ =
√3/2
2/√3
1/2
2
cosec 74 + tan 81 equal to
sec18 + cot 10
sec17+ cot 11
sec16 + cot 9
sec19+ cot 12
If a sin θ = 1 and b tan θ = 1, then the relation between a and b is
a2 = b2
a2 - b2 = 1
a2 + b2 = 1
a2 + b2 = -1
If cosec θ = √5, then cot θ - cos θ =
If sec θ = 2 then sin θ =
3/2
1/√3
If cosec θ = √2, then cot θ =
0
1
√2 + 1
√2 - 1
sin θ × _______ = 1
cos θ
cosec θ
sec θ
cot θ
sin2 50+ cos2 50 =
1.25
2.32
