The solution of differential equation ( 1 - y ) x dy/dx + ( 1 + x ) y = 0 is
log xy + x + y = c
log xy + x -y =c
log xy - x - y = c
The solution of differential equation dy/dx + y tan x = sec x is
sin x
( sin x ) -1
e sin x
( cos x ) -1
The solution of differential equation is.
(1 + y2 ) (1 + x 2 ) = cx2
(1 - y2 ) (1 + x 2 ) = cx2
(1 + y2 ) (1 - x 2 ) = cx2
(1 - y2 ) (1 - x 2 ) = cx2
The solution of differential equation is
sin -1 y + sin -1 x = c
sin -1 y - sin -1 x = c
sin -1 x + 2 sin -1 y = c
2 sin -1 y - sin -1 x = c
The solution of differential equation dy/dx + y/x = x2 is.
4xy = x4 + c
xy = x4 + c
4xy - x4 + c
None of these
The integrating factor of the differential equation ( 1 + y2 ) dx - ( tan -1 y - x ) dy = 0 is
tan - 1 y
e tan -1 y
1/ 1 + y2
1/ x ( a + y2 )
The solution of differential equation x dy/dx = y ( log y - log x + 1 ) is
Log x/y = cy
Log y/x = cy
log x/y = cx
lot y/x = cx
log ( 1 + y2 ) = tan -1 x + c
The solution of differential equation (x2 - y2 ) dy/dx = xy is .
On putting y = vx, the homogeneous DE x2dy + y ( x + y) dx = 0 becomes :
xdv + ( 2v + V2 ) dx = 0
vdx + (2x + x2) dv =0
V2dx - ( x + x2 ) dv = 0
vdv + ( 2x + x2 ) dx = 0
