A particle is executing S.H.M. with an amplitude of 4 cm and time period 12 seconds. The time taken by the particle in going 2 cm from the mean position is T1 seconds. The time taken from this displaced position to reach the extreme position on the same side is T2 seconds. Then T1 /T2 will be
2
1
1/3
1/2
The acceleration of a particle in S.H.M. is
always constant
maximum at extreme positions
maximum at mean position
always zero
Frequency of a simple pendulum in a freely falling lift is
zero
infinite
finite
cannot say