If the length of the diagonal of a square is increasing at the rate of 0.2 cm/sec,then the rate of increase of its area when the side is is
3cm2/sec
The value of
2
-2
-1
1
The equation of the normal to the curve Q = 1/t at the point (-3,-1/3) is
3 Q = 27 t - 80
5 Q = 27 t - 80
3 Q = 27 t + 80
Q = 1/t
If V=,at what rate in cubic unit S in V increasing , where r =10 and =0.01 ?
The equation of the tangent to the curve at the point is
5 y + 3 x = 2
5 y - 3 x = 2
3 x - 5 y = 2
3 x + 3 y = 2
The slope of the normal to the curve y = 3 x2 at the point where x - co ordinate 2 is
1/13
1/14
-1/12
1/12
A cone whose height is always equal to its diameter is increasing in Volume at the rate of 40 cm2 /sec . At what rate is the radius increasing when its circular base area is 1m2 ?
1mm/sec
0.001 cm/sec
2 mm/sec
0.002 cm/sec
What is the surface area of a sphere when the volume is increasing at the same rate as its radius?
1/2λ
4λ
For what values of x, the rate of increase of x3 -5x2 +5x+6 is twice the rate of increase of x ?
1, 7/3
3, 1/3
3, 7/3
1/3, 7/3
For the curve x = t2-1, y = t2 - t, the tangent is perpendicular to x - axis when
t = 0
t = l
