x3 - 27 =
(x-3) (x-9)
(x-3) (x2-3 x+9)
(x-3) (x2+3 x+9)
(x-3)3
x3+27 =
(x+3) (x2+3 x+9)
(x+3) (x2-3 x+9)
(x2+2)2=
x2+ 4 x+4
x2- 4 x+4
x4+ 4 x+4
x4+ 4 x2+4
Which is the constant term of 5 x2+ 10 x+1
1
10
5
10x
(x+a) (x+b)
x2+ab x+ab
x2+ (a+b)x+ ab
x2+(ab+b)x+ab
ax2+bx+ab
The expression (10.5 x 10.5 - 10.5 x 4.5+4.5 x 4.5) (10.5+4.5) is in the form of
(a+b)2
(a-b)2
a3-b3
a3+b3
(x - 4) (x + 3) =
x2 + x - 12
x2 - 7 x - 12
x2 + 7 x + 12
x2 - x - 12
Splitting of x- term in 3 x2- 11 x + 6 is
-11, -1
-9,-2
-5,-6
-7,-4
If one factor of 8 x3+27 y3+18 xy-1 is (2 x+3 y - 1) then the other is
4 x2+9 y2+1
4 x2+9 y2-1
4 x2+9 y2+1 -6 xy+3 y+2 x
4 x2+9 y2+1 +6 xy-3 y-2 x
(a+b) (a2-ab+b2) =
a3- b3
a3+b3 -3ab
0