The number of terms of A.P 3, 7, 11, 15. . . where the sum is 406 is
5
10
12
14
The A.M between pth and qth terms of an A.P is equal to the AM between rth and sth terms of the A.P. Then p+q =
r + s
r - s/r + s
r + s/r - s
r + s + 1
10th term of an A.P is 52, 16th term is 82 then tn will be
n + 2
5n - 2
5n + 2
5n
The first 3 terms of the sequence an = (n+1)/(n+2) is
5/4, 4/3, 3/2
2/3, 3/4, 4/5
4/5, 3/4, 2/3
4, 3, 2
How many terms of the G.P 3, 3/2, 3/4......... are needed to give the sum 3069/512?
11
9
8
If the nth term of an AP is 6n - 1. Then its (n + 1)th term is
6n + 4
6n + 5
6n - 4
6n - 5
1 + 2 + 3 +........30 =
465
930
900
500
If -2/7, x, -7/2 are in G.P, then x =
1
-1
± 1
None of these
The sum to the first 25 terms of the series 1 + 2 + 3......... is
305
325
315
335
Which terms of the G.P 2, 2√2, 4,........ is 128?
13
15