If x > y > 0 where a > 1, then ?
log ax > log ay
logax < logay
logax ≥ logay
log ax = log ay
A student was asked to prove a statement P (n) by method of induction. He proved that P (3 ) is true such that P (n) = P (n + 1 ) for all
n ∈ N
n ≥ 3
n ∈ I
n < 3
The number 101 x 102 x 103 x 104 x ..... x 107 is divisible by .
4000
4050
5040
5050
All possible two - factor products are from the digits 1,2,3,4, ...., 200. The number of factors out of the total obtained, which are multiples of 5, is
8040
7180
6150
4040
The expression 3 2n + 2 - 8n - 9 is divisible by 64 for all
n ∈ N, n < 2
n ∈ N n ≥ 2
n ∈ N, n > 2
The statement P (n ): ( 1 x 1! ) + (2 x 2! ) + (3 x 3! ) + .... + ( n x n !) = ( n + 1 )! - 1' is
True for all values of n > 1
Not true for any value of n
True for all values of n ∈ N
None of these
If a and b are natural numbers such that a2 - b2 is a prime number, then
a2 - b2 = 1
a2 - b2 = 2
a2 - b2 = a - b
a2 - b2 = a + b
The unit digit in the number 7126 is
1
3
9
5
If x > -1, then the statement ( 1 + x ) n > 1 + nx is true for
All n < 1
All n > 1
All n ∈ N
All n > 1 provided x ≠ 0
The solution of the inequality 2x2 + x - 15 ≥ 0 is