The equation of a line passing through the intersection point of lines x - 2y = 1 and x + 3y = 2 and parallel to lines 3x + 4y = 0 is.
3x + 4y + 5 = 0
3x + 4y - 10 = 0
3x + 4y - 5 = 0
3x + 4y + 6 = 0
The coordinates of foot of perpendicular from (2,3 ) to the line x + y -11 = 0 are
(-6,5)
(5,6)
(-5,6)
(6,5)
The ortho centre of the triangle formed by vertices (0,0) , (8,0) and (4,6) is
(3,4)
(4,3)
(-3,4)
(4, 8/3)
The intersection point of lines and lie on
x - y = 0
(x + y) (a + b) = 2 ab
(x + my) (a + b) = (l + m) ab
None of these
The coordinates of foot of perpendicular from origin to the line 3x+4y -5 = 0 is
Line L is perpendicular to line 5x - y = 1.The area of triangle formed by coordinates axis and line is 5 sq . units.Then its equation is
x + y = √2
x + 5y = ± 5 √2
x + 5y = -5
x + 5y = - √2
The angle between lines y = (2 - √3) x + 5 and y = (2 + √3) x - 7 is.
30^{o}
45^{o}
60^{o}
90^{o}
The angle between lines 3x + y - 7 = 0 and x + 2y + 9 = 0 is
120^{o}
135^{o}
180^{o}
The equation of sides of a quadrilateral AB,BC,CD, and DA are x + 2y = 3, x = 1, x - 3y = 4,5x + y + 12 = 0, the angle between diagonals AC and AD is
If two vertices of any triangle are (5,-1) and (-2,3) and if ortho-centre is on the origin,the coordinate of third vertex is
(7, 4 )
(-4 , 7)
(4 , -7)
(-4 , -7)