The lines passing through (3,2) and inclined at angle 60^{o} with √3 x + y = 1 is.
y + 2 = 0
x + 2 = 0
x + y = 2
x - y = √3
Point (0,0), (2,-1) and (9,2) are vertices of a triangle , then cos B =
11/290
√11/290
-11/√290
-√11/290
The coordinates of points which lie on line x + y = 4 and whose distance from 4x + 3y = 10 is unity are
(3,1) (-7,11)
(3,1) (7,11)
(-3,11) (-7,11)
(1,3) (-7,11)
The length of perpendicular from origin to the line is.
The ortho-center of triangle whose vertices are (0,0) , (3,0) and (0,4) is.
(0,0)
(1,1)
(2,2)
(3,3)
The equation of line which passes through (1,-2) and cuts equal intercepts with coordinate axis is.
x + y = 1
x - y = 1
x + y + 1 = 0
x - y - 2 = 0
The coordinates of foot of perpendicular from origin to the line 3x+4y -5 = 0 is
The angle between lines and is.
If in the equation y - y_{1} = m (x - x_{1}) , m and x , remain constant different lines are drawn for different values of y_{1} , then.
Lines are concurrent
A set of parallel lines is obtained
Only one line is possible
None of these
The equation of line passing through (c , d) and parallel to ax + by + c = 0 is
a (x +c ) + b ( y + d) = 0
a (x + c) - b (y + d) = 0
a (x - c) + b (y + d) = 0
a (x - c) - b (y - d) = 0