The escape velocity from earth is 11.2 km/s. If a body is to be projected in a direction making an angle 45o to the vertical, then the escape velocity is
11.2 × 2 km/s
11.2 km/s
11.2/√2 km/s
11.2√2 km/s
The period of revolution of planet A around the sun is 8 times that of B. The distance of A from the sun is how many times greater than that of B from the sun?
5
4
3
2
If the gravitational force between two object were proportional to 1/R (and not as 1/R2), where R is separation between them, then a particle in circular orbit under such a force would have its orbital speed v proportional to
1/R2
R0
R
1/R
A body attains a height equal to the radius of the earth. The velocity of the body with which it was projected is
A body of mass m is placed on earth's surface. It is then taken from earth's surface to a height h = 3R, then the change in gravitational potential energy is
mgh/R
2/3 mgR
3/4 mgR
mgR/2
For a satellite escape velocity is 11 km/s. If the satellite is launched at an angle of 60o with the vertical, then escape velocity will be
11 Km/s
11√3 Km/s
11/√3 Km/s
33 Km/s
A planet is moving in an elliptical orbit around the sun.If T, U, E and L stand for its kinetic energy, gravitational potential energy, total energy and magnitude of angular momentum about the centre of force, which of the following is correct?
T is conserved
U is always positive
E is always negative
L is conserved but direction of vector L changes continuously
The escape velocity of a sphere of mass m is given by (G = universal gravitational constant, Me = mass of earth and Re = radius of earth)
The acceleration due to gravity on the planet A is 9 times the acceleration due to gravity on planet B. A man jumps to a height of 2m on the surface of A. What is the height of jump by the same person on the planet B?
6 m
2/3 m
2/9 m
18 m
The satellite of mass m is orbiting around the earth in a circular orbit with a velocity v. What will be its total energy?
3/4 mv2
1/2 mv2
mv2
- (1/2)mv2